Question

当执行以下功能时，我收到错误消息：

UnhandledPromiseRejectionWarning: Unhandled promise rejection (rejection id: 362): TypeError: request(...).then is not a function

我不知道此错误消息的原因，但我认为它与我的请求有关。根据{{3}}的“请求 - 承诺”我的代码如果格式正确。

const request = require('request-promise');

addressFunction(lat,lon){
var error = "No Address Data"
var addressExist = true;

return new Promise(
  function(resolve){
    if(addressExist) {
      let apiKey = "API-Key";
      let geocodeAddress = "https://maps.googleapis.com/maps/api/geocode/json?latlng=" + lat + "," + lon + "&key=" + apiKey;

      resolve(
        request(geocodeAddress).then(res => {
          res = JSON.parse(res);
          newAddress = res.results[0].formatted_address.replace(/^\d+\s*/, '');
          newAddress = newAddress.split(',', 3).join(',').replace(/[0-9]/g, '').trim()
          return newAddress
        })
      );
    } 
  }
);

} }

我尝试传递“选项”参数，例如

var options = {
uri: 'http://www.google.com',
transform: function (body) {
    return cheerio.load(body);
}

虽然那仍然没有奏效。

任何人都知道为什么请求...然后抛出错误？

Answer 1

你做错了。你需要resolve(newAddress)而不是整个api召唤承诺

function someFunction () {
   return new Promise(function(resolve, reject){
    if(addressExist) {
      let apiKey = "API-Key";
      let geocodeAddress = "https://maps.googleapis.com/maps/api/geocode/json?latlng=" + lat + "," + lon + "&key=" + apiKey;

     request(geocodeAddress).then(res => {
          res = JSON.parse(res);
          newAddress = res.results[0].formatted_address.replace(/^\d+\s*/, '');
          newAddress = newAddress.split(',', 3).join(',').replace(/[0-9]/g, '').trim()
          resolve(newAddress);
        }).catch(error => {
          console.log(error);
          resolve('some other values based on logic');
        });

    } else {
       resolve('some other value based on logic');
    }
  }
);
}

Javascript promise request ...然后返回undefined，尽管它存在

1 个答案: