Question

我已经为我想要制作的基于文本的游戏创建了一个GUI。我将GUI实现到已经运行的游戏机制中，但是当我加载它时，GUI不会出现。页面上没有错误，eclipse将运行游戏的其余部分，而不是与GUI相关的任何内容。（我已经为GUI添加了整个代码，但只包含游戏的一部分来缩短代码。）代码如下：

public static void main(String[] args) {
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                DemoGUI inst = new DemoGUI();
                inst.setLocationRelativeTo(null);
                inst.setVisible(true);
            }
        });
    }
    public DemoGUI() {
        super();
        initGUI();
    }
    public void initGUI() {
        try {
            FlowLayout thisLayout = new FlowLayout();
            getContentPane().setLayout(thisLayout);
            setDefaultCloseOperation(EXIT_ON_CLOSE);

                jLabel1 = new JTextArea();
                getContentPane().add(jLabel1);
                jLabel1.setPreferredSize(new Dimension(320, 250));
                jLabel1.setBorder(BorderFactory.createLineBorder(Color.BLACK));

                jButton1 = new JButton();
                getContentPane().add(jButton1);
                jButton1.setPreferredSize(new Dimension(100, 50));
                jButton1.setText("Map");
                jButton1.addActionListener(new ActionListener(){
                    public void actionPerformed(ActionEvent e) {
                    }
                });

                jButton2 = new JButton();
                getContentPane().add(jButton2);
                jButton2.setPreferredSize(new Dimension(100, 50));
                jButton2.setText("Inventory");
                jButton2.addActionListener(new ActionListener(){
                    public void actionPerformed(ActionEvent e) {
                        jText1.setText("Health: " + EAID.CharHealth);
                        jText1.setText("Number of potions: " + EAID.CharPotionLevel);
                        jText1.setText("Weapon: ");
                        jText1.setText("Armor: ");
                    }
                });

                jButton4 = new JButton();
                getContentPane().add(jButton4);
                jButton4.setPreferredSize(new Dimension(100, 50));
                jButton4.setText("Return");
                jButton4.addActionListener(new ActionListener(){
                    public void actionPerformed(ActionEvent e) {
                        jLabel1.setText("");
                        jText1.setText("");
                    }
                });

                jText1 = new JTextField();
                getContentPane().add(jText1);
                jText1.setPreferredSize(new Dimension(320, 100));
                jText1.setBorder(BorderFactory.createLineBorder(Color.BLACK));

                jButton3 = new JButton();
                getContentPane().add(jButton3);
                jButton3.setPreferredSize(new Dimension(100, 40));
                jButton3.setText("Submit");
                jButton3.addActionListener(new ActionListener(){
                    public void actionPerformed(ActionEvent e) {
                        jText1.setText("");
                        jLabel1.setText("THIS IS A TEST");
                    }
                });


                //Scanner   
                Scanner scan = new Scanner(System.in);
            //Introduction  
                jLabel1.setText("Hello adventurer. This is a tale of old, taking place in the long lost kingdom of Asteroth.\r\n" + 
                    "This is a land tormented by the tyranical rule of the Lich King Astotle.\r\n" + 
                    "For centuries he has tormented the citizens, leading to widespread famine and terror throughout the land.\r\n" + 
                    "The story you are about to go on follows the tale of a young hero, on there quest to bring peace to the land.\r\n" + 
                    "But tell me adventurer..");

在关闭类和主字符串之前，它会添加到文档的最底部：

pack();
            this.setSize(350, 500);
        } catch (Exception e) {
            e.printStackTrace();
        }

Answer 1

删除扫描仪允许GUI加载

因此，您无法在事件发送线程（EDT）上执行扫描程序。

因此，您需要为Thread创建另一个Scanner。一种方法是使用SwingWorkder。

阅读Concurrency上Swing教程中的部分，了解有关EDT的更多信息以及使用SwingWorker的示例。

我的GUI无法加载

1 个答案: