Question

想象一下我有一个元组，其中包含一个列表。

例如：

t = (1, 2, 3, 4 [5, 6, 7])

好吧，我想把它们保存在元组和列表中的所有数字。我怎么做？在另外我知道如何获取它们在元组中保存的数字。我只需解压缩元组并获取所有数字，保存在lis中，我会迭代它。但在这种情况下，我不知道自己该做什么。

有什么想法吗？

了解详情

def work_with_tuple(my_tuple = None):

    count_items = len(my_tuple)

    if count_items == 2:

        first_item, second_item = my_tuple

        print "first_item", first_item
        print "second_item", second_item

    if count_items == 3:

        first_item, second_item, third_item = my_tuple

        print "first_item", first_item
        print "second_item", second_item

        # But I have to know, that 'third_item' is a list.
        # Should I check every unpacked item if it is a list?
        # I think my idea it doesn't sound elegance.
        one, two = third_item
        print "one", one
        print "two", two

print "run first"
print "---------"
#   I call the function with easy tuple
work_with_tuple(my_tuple = (2, 3))
#   output: first_item 2
#           second_item 3
print ""
print "run second"
print "----------"
#   I call the function with nested tuple
work_with_tuple(my_tuple = (2, 3, [4, 6]))
#   output: first_item 2
#   second_item 3
#   one 4
#   two 6

Answer 1

您可以迭代元组并检查每个项目。

def unpack(t):
    numbers = []

    for item in t:
        if isinstance(item, list):
            numbers += item # add each item of the list into accumulator
        else:
            numbers.append(item)

    return numbers

如果您需要更通用的内容，请参阅this answer。

Answer 2

通过这种方式访问元组中的列表。

tl = (1,2,3,4,[5,6,7])
print tl
for i in tl:
    if isinstance(i, list):
        print i[2]
    else:
        print i

希望您的问题正在使用我的代码解决。

如何访问元组中的列表？

2 个答案: