Question

这是我的字符串：

您的交易的一次性密码，在您的xxxx银行'借记/贷记/存款/ ....'的'xxxx'为inr'1897.00'，结尾为'0000'的卡是0000“

xxxx - 字符串，0000 - 数字

我想用单引号（'）

获取所有值

这就是我的尝试：

[a-z ]+, ([a-z]+)[a-z ]+([0-9\.]+)直到这里才是正确的

现在我想获取（借记/贷记/ ...），我正在做：

在[a-z]+银行[a-z]+[a-z ]+([0-9]+)[a-z ]+[0-9]
上

什么应该是更好的方式？

Answer 1

您正在寻找的正则表达式只是r"'(.*?)'"。下面是一个示例程序：

import re

regex = r"'(.*?)'"

test_str = "\"one time password for your transaction at, 'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000\""

matches = re.finditer(regex, test_str)

for matchNum, match in enumerate(matches):
    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

哪个输出：

Match 0 was found at 44-50: 'xxxx'
Match 1 was found at 58-67: '1897.00'
Match 2 was found at 86-113: 'debit/credit/deposit/....'
Match 3 was found at 126-132: '0000'

在此处详细了解如何使用正则表达式：https://regex101.com/

Answer 2

如果你想要单引号中的所有字符，

import re
string = "'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000"
all_matches = re.findall(r"\'.+?\'",string)
print all_matches

Answer 3

最安全，最高效的方法是匹配两个不是单引号的单引号之间的任何内容（在这种情况下，贪婪或懒惰无关紧要）：

'[^']*'

Demo

代码示例：

import re    
regex = r"'[^']*'"    
test_str = '''one time password for your transaction at, 'xxxx' of inr '1897.00' \
on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000'''
matches = re.finditer(regex, test_str)
for match in matches:
    print ("Match was found at {start}-{end}: {match}".format(start = match.start(), end = match.end(), match = match.group()))

python：使用正则表达式查找特定单词

3 个答案: