Question

我创建了一个python脚本，其中有4个空列表，代码在这些列表上创建一个随机数，最后将其保存为Excel文件。问题在于它用浮点数创建数字，我只想要整数！有人能帮助我吗？

这是我的代码：

import numpy as np
import openpyxl
import random

from openpyxl import Workbook

# Create workbook object
wb = openpyxl.Workbook()
sheet = wb.get_active_sheet()

sheet.title = 'Sheet #1'



# Generate data

Timestamp = [0, 1, 2, 3, 4, 5, 6, 7,8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23]

Subtotal_vest = []

Subtotal_NorthEast = []

Subtotal_south = []

Others = []



for i in Timestamp:
    Subtotal_vest.append(random.gauss(3640, 25)),
    Subtotal_NorthEast.append(random.gauss(3832, 25)),
    Subtotal_south.append(random.gauss(2592, 25)),
    Others.append(random.gauss(1216, 25)),







#y = x * x

# Add titles in the first row of each column
sheet.cell(row=1, column=1).value = 'Timestamp'
sheet.cell(row=1, column=2).value = 'Vest'
sheet.cell(row=1, column=3).value = 'North east'
sheet.cell(row=1, column=4).value = 'South'
sheet.cell(row=1, column=5).value = 'Others'

#sheet.cell(row=1, column=2).value = 'Y values'

# Loop to set the value of each cell

for inputs in range(0, len(Timestamp)):
    sheet.cell(row=inputs + 2, column=1).value = Timestamp[inputs]
    sheet.cell(row=inputs + 2, column=2).value = Subtotal_vest[inputs]
    sheet.cell(row=inputs + 2, column=3).value = Subtotal_NorthEast[inputs]
    sheet.cell(row=inputs + 2, column=4).value = Subtotal_south[inputs]
    sheet.cell(row=inputs + 2, column=5).value = Others[inputs]



# Finally, save the file and give it a name
wb.save('Excel/Matrix.xlsx')

Answer 1

把它扔到那里作为另一种选择。对于任意分布，您可以创建其累积分布函数（CDF），然后从统一随机分布中抽取该样本百分位数。然后，您需要将它们转换为整数，但这可以让您从任何所需的分布中进行绘制！

from scipy.stats import norm
import matplotlib.pyplot as plt
# Replace `mean` and `std` below with your existing means and standard deviations.
draw = norm.ppf(np.random.random(1000), loc=mean, scale=std)  # 1000 samples, for example
plt.hist(draw.astype(int))

这种方法的一个好处是它适用于您可以创建CDF的任何发行版;即使你只能用数据来定义数字！

或者，您可以使用二项分布逼近正态分布，二项分布是离散的。一般来说，B(n, p) ~ N(n*p, sqrt(n*p*(1-p)))：

draw = np.random.binomial(n, p, size=1000)

您必须设置n和p，才能从原始均值和标准差中求解n*p = mean和sqrt(n*p*(1-p)) = std。

Answer 2

或者您可以使用numpy.random.normal()：

import numpy as np

Timestamp = [0, 1, 2, 3, 4, 5, 6, 7,8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23]
timestamps = len(Timestamp)

Subtotal_vest = np.random.normal(3640, 25, timestamps).astype(int)
Subtotal_NorthEast = np.random.normal(3832, 25, timestamps).astype(int)
Subtotal_south = np.random.normal(2592, 25, timestamps).astype(int)
Others = np.random.normal(1216, 25, timestamps).astype(int)

Answer 3

如果您对使用统一分布绘制的随机数字感到满意，则可以使用random.randint代替random.gauss。

Answer 4

您是否尝试使用int(random.gauss(...))？

Answer 5

将random.gauss返回的值转换为int将执行：

import numpy as np
import openpyxl
import random

from openpyxl import Workbook

# Create workbook object
wb = openpyxl.Workbook()
sheet = wb.get_active_sheet()
sheet.title = 'Sheet #1'

# Generate data
timestamp = [
    0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
    10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
    20, 21, 22, 23
]
subtotal_vest = []
subtotal_north_east = []
subtotal_south = []
others = []

for i in timestamp:
    subtotal_vest.append(int(random.gauss(3640, 25))),
    subtotal_north_east.append(int(random.gauss(3832, 25))),
    subtotal_south.append(int(random.gauss(2592, 25))),
    others.append(int(random.gauss(1216, 25))),


#y = x * x

# Add titles in the first row of each column
sheet.cell(row=1, column=1).value = 'Timestamp'
sheet.cell(row=1, column=2).value = 'Vest'
sheet.cell(row=1, column=3).value = 'North east'
sheet.cell(row=1, column=4).value = 'South'
sheet.cell(row=1, column=5).value = 'Others'

#sheet.cell(row=1, column=2).value = 'Y values'

# Loop to set the value of each cell

for inputs in range(0, len(timestamp)):
    sheet.cell(row=inputs + 2, column=1).value = timestamp[inputs]
    sheet.cell(row=inputs + 2, column=2).value = subtotal_vest[inputs]
    sheet.cell(row=inputs + 2, column=3).value = subtotal_north_east[inputs]
    sheet.cell(row=inputs + 2, column=4).value = subtotal_south[inputs]
    sheet.cell(row=inputs + 2, column=5).value = others[inputs]

# Finally, save the file and give it a name
wb.save('Matrix.xlsx')

Answer 6

替换

Subtotal_vest = []

Subtotal_NorthEast = []

Subtotal_south = []

Others = []



for i in Timestamp:
    Subtotal_vest.append(random.gauss(3640, 25)),
    Subtotal_NorthEast.append(random.gauss(3832, 25)),
    Subtotal_south.append(random.gauss(2592, 25)),
    Others.append(random.gauss(1216, 25)),

带

Subtotal_vest = [int(round(random.gauss(3640, 25))) for _ in Timestamp]
Subtotal_NorthEast = [int(round(random.gauss(3832, 25))) for _ in Timestamp]
Subtotal_south = [int(round(random.gauss(2592, 25))) for _ in Timestamp]
Others = [int(round(random.gauss(1216, 25))) for _ in Timestamp]

round舍入到最接近的整数＆amp;然后int将浮点数转换为整数。

Answer 7

使用int（rd.gauss（mu，sigma））。

大卫

Answer 8

使用random.randint(0,10)代替random.gauss。 random.randint（）生成随机整数值。

生成只有整数的随机数，而不是浮点数

8 个答案: