Question

我有一个String数组，我想使用Java 8流将其转换为BigInteger数组。

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这是我尝试的但是我无法获得BigInteger数组，但是我能够获得Object数组。

String[] output = bigSorting(new String[]{"31415926535897932384626433832795", "1", "4900146572543628830293235422623540449026979", "10", "57500297590012603652986133599394871645776460", "5", 
                    "497010206818067722087306230802257700034825862515267073569769100385728461314", "57500297590012603652986133599394871645776460497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314"});
        Object[] unsortedBigIntegerArr = convertFromStringArrayToBigIntegerArray(output);

我有什么方法可以完全使用Java 8流。

Answer 1

简单如下：

return Arrays.stream(unsorted)
             .map(BigSorting2::convertFromStringToBigInteger)
             .toArray(BigInteger[]::new);

Answer 2

非常简单的事情：

public void test(String[] args) {
    String[] output = new String[]{"31415926535897932384626433832795", "1", "4900146572543628830293235422623540449026979", "10", "57500297590012603652986133599394871645776460", "5",
            "497010206818067722087306230802257700034825862515267073569769100385728461314", "57500297590012603652986133599394871645776460497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314497010206818067722087306230802257700034825862515267073569769100385728461314"};
    Object[] bigIntegers = Arrays.stream(output)
            .map(BigInteger::new)
            .toArray();
    System.out.println(Arrays.toString(bigIntegers));
}

如何使用Java 8流将字符串数组转换为Big-integer数组

2 个答案: