Question

我正在寻找以下案例的解决方案。让我们假设以下结构给出了数据：

CREATE TABLE IF NOT EXISTS `customer_prices` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `customer` int(11) unsigned NOT NULL,
  `price` decimal(8,2) unsigned DEFAULT NULL,
  `date` date NOT NULL DEFAULT '0000-00-00',
  PRIMARY KEY (`id`),
  UNIQUE KEY `item_id_period` (`customer`,`date`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci ROW_FORMAT=DYNAMIC;

INSERT INTO `customer_prices` (`id`, `customer`, `price`, `date`) VALUES
    (131739296, 1, 12.56, '2018-01-01'),
    (131739297, 1, 18.33, '2018-01-02'),
    (131739301, 1, 15.66, '2018-01-03'),
    (131739302, 1, 35.40, '2018-01-04'),
    (131739303, 1, 16.96, '2018-01-05'),
    (131739304, 1, 11.90, '2018-01-06'),
    (131739305, 1, 17.31, '2018-01-07'),
    (131739306, 1, 15.75, '2018-01-08');

执行以下查询

SELECT 
AVG(price) + AVG(price) / 100 * 10 AS maxprice,
AVG(price) - AVG(price) / 100 * 10 AS minprice,
GROUP_CONCAT(price)
FROM customer_prices 
WHERE date > '2018-01-01' AND date < '2018-01-07'

将生成价格清单

18.33, 15.66, 35.40, 16.96, 11.90

我想要的是将这个清单价格限制在minprice和maxprice之间。

我试图这样做，但给了我错误。

SELECT 
GROUP_CONCAT(price)
FROM customer_prices 
WHERE date > '2018-01-01' AND date < '2018-01-07'
AND price > (AVG(price) - AVG(price) / 100 * 10)
AND price < (AVG(price) + AVG(price) / 100 * 10)

这有解决方法吗？谢谢！

group_concat过滤器价格

0 个答案: