我真的找不到从下面输出中获取用户价值的方法
如果我直接打印结果,我会
(TotersAPIFrameWork.Result<TotersAPIFrameWork.DataContainer<TotersAPIFrameWork.User>>) $R5 = success {
success = {
user = {
id = 200
first_name = "yara"
last_name = "Padberg"
email = "client@client.com"
phone_number = "+9999"
type = "client"
account_type = "email"
sm_user_id = nil
sm_access_token = nil
picture = ""
deleted_at = nil
created_at = "2018-04-04 14:33:29"
updated_at = "2018-04-24 11:15:45"
rating = "5"
rating_count = 1
regid = ""
platform = "ios"
is_agora = nil
currency_id = 1
is_verified = true
promo_code_id = nil
referral_promo_code_id = nil
op_city_id = 1
is_daas = false
token = ""
retailer_info = nil
}
}
}
我尝试直接转换为下面的用户
p result as? User
它返回nil,那么我应该如何从DataContainer获得结果?
感谢您的帮助
答案 0 :(得分:1)
在花了更多时间并了解我正在处理的事情之后:)我想出了如何获得用户对象。
首先,我使用的结果是一个枚举,我的回调正在返回结果,所以下面是解决方案:
let login = PostLogin.init(email: "client@client.com", password: "pass")
let client = APIClient(publicKey: "", privateKey:"")
client.send(login) { (result) in
switch result {
case .success(let value):
print(value)
case .failure(let error):
print(error)
}
}
结果是枚举:
import Foundation
public enum Result<Value> {
case success(Value)
case failure(Error)
}
public typealias ResultCallback<Value> = (Result<Value>) -> Void
价值结构如下:
import Foundation
/// All successful responses return this, and contains all
/// the metainformation about the returned chunk.
public struct DataContainer<T: Decodable>: Decodable {
public var user:T?
public init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: UserResponseKeys.self)
if let u = try container.decodeIfPresent(T.self, forKey: .user)
{
self.user = u
}
}
}
现在我可以得到这样的用户:
let user = value.user
希望这会有所帮助。