使用内部联接根据类别过滤产品

时间:2018-04-24 11:13:55

标签: php sql inner-join data-retrieval

SQL查询正确地从数据库中选择所需的产品,但是我无法让php将数据输出到网站。我需要数据也在下面的HTML中。 if statement块内部有问题,但我根本找不到它

SQL:

CREATE TABLE Product(
    Product_ID int NOT NULL AUTO_INCREMENT,
    Name varchar(255) NOT NULL,
    Stock_Level int NOT NULL,
    Price int NOT NULL,
    Image blob NOT NULL,
    Admin_ID int NOT NULL,
    PRIMARY KEY (Product_ID),
    FOREIGN KEY (Admin_ID) REFERENCES Admins(Admin_ID)
);

CREATE TABLE Category(
    Category_ID int NOT NULL AUTO_INCREMENT,
    Category varchar(15) NOT NULL,
    PRIMARY KEY (Category_ID)
);

CREATE TABLE ProductLookup(
    ProductLookup_ID int NOT NULL AUTO_INCREMENT,
    Product_ID int(100) NOT NULL,
    Category_ID int NOT NULL,
    PRIMARY KEY (ProductLookup_ID),
    FOREIGN KEY (Product_ID) REFERENCES Product(Product_ID),
    FOREIGN KEY (Category_ID) REFERENCES Category(Category_ID)
);

PHP:

   <?php
  //Connect to DB
  include_once 'DBConnection.php';

 //Query DB to find Meat Products based on category

  $sql = "SELECT p.Name, p.Price, p.Image FROM Product p INNER JOIN (ProductLookup pl) ON (p.Product_ID = pl.Product_ID) WHERE pl.Category_ID = 1;";

 $result = mysqli_query($conn, $sql);
 $resultCheck = mysqli_num_rows($result);
 if($resultCheck > 0){
   while($row = mysqli_fetch_assoc($result)){
      echo $row['Name'];
      echo $row['Price'];
      echo $row['Image'];
   }
} else{
  echo "Empty";
}
?>

HTML

<div class="panel-body">
                <div class="row">
            <div class="col-md-4 product">
                <div class="product-price">£000</div>
                <a href="product.html">
                    <img src="#"/>
                </a>
                <div class="product-title">
                    Placeholder
                </div>
                <div class="product-add">
                    <?php
                    if(isset($_SESSION['id'])){
                     echo '<button class="btn btn-primary" type="submit">Add To Basket</button>';
                    }else{
                        echo 'Please <a href="login.php">Log In to Purchase</a>';
                    }
                    ?>
                </div>
            </div>
        </div>
    </div>

1 个答案:

答案 0 :(得分:0)

你有两个问题:

第一个是查询中的错误。您正在尝试从Products表中获取数据,但表的名称是Product

尝试此查询:

SELECT p.Name, p.Price, p.Image
FROM Product p
INNER JOIN (ProductLookup pl) ON (p.Product_ID = pl.Product_ID)
WHERE pl.Category_ID = 1

第二个是该行的错误:

while($row = msqli_fetch_assoc($result)){

函数msqli_fetch_assoc适用于Microsoft数据库,而不适用于MySQL。你可以用这个:

while ($row = mysqli_fetch_assoc($result)) {

我制作了以下代码,效果很好:

<?php

//Connect to DB
$conn = mysqli_connect('localhost', 'user', 'password', 'database');

//Query DB to find products
$sql = "SELECT Products.Name, Products.Price, Products.Image 
FROM Products 
INNER JOIN ProductLookup ON Products.Product_ID = ProductLookup.Product_ID 
WHERE ProductLookup.Category_ID = 1;";

$sql = "
SELECT p.Name, p.Price, p.Image
FROM Product p
INNER JOIN (ProductLookup pl) ON (p.Product_ID = pl.Product_ID)
WHERE pl.Category_ID = 1
";

$result = mysqli_query($conn, $sql);
$resultCheck = mysqli_num_rows($result);

?>


<div class="panel-body">
    <div class="row">

<?php

if ($resultCheck > 0) {

    while ($row = mysqli_fetch_assoc($result)) { ?>

        <div class="col-md-4 product">
            <div class="product-price">
                £<?= $row['Price'] ?>
            </div>
            <a href="product.html">
                <img src="<?= $row['Image'] ?>"/>
            </a>
            <div class="product-title">
                <?= $row['Name'] ?>
            </div>
            <div class="product-add">
                <?= isset($_SESSION['id']) ? '<button class="btn btn-primary" type="submit">Add To Basket</button>': 'Please <a href="login.php">Log In to Purchase</a>' ?>
            </div>
        </div>

    <?php }

} else {

    echo "<h2>There is no products avaliable</h2>";

}

?>

    </div>
</div>