您好我已经使用stateprovider
很长一段时间了,这次我想实现一个功能,在不更改网址的情况下,我想要not found state
而不是网址。
这是我的代码。
(function () {
angular.module('mean').config(aosOfferConfig);
function aosOfferConfig($stateProvider, $urlRouterProvider) {
$urlRouterProvider.otherwise("/link/404_not_found");
$stateProvider
.state('offers', {
url: '/offers/packages',
templateUrl: 'views/aosOffers/aosoffers.html',
controller: 'offersController',
controllerAs: 'packages'
})
.state('offersignup', {
url: '/offers/signup',
templateUrl: 'views/aosOffers/offerssignup.html',
controller: 'offersSignupController',
controllerAs: 'offerssignup'
})
.state('thankyou', {
url: '/offers/thankyou',
templateUrl: 'views/aosOffers/offersthankyou.html'
});
}
})();
现在在我的另一部分,我将用户带到/link/404_not_found
。我不想要这个。相反,我希望它将保留在当前URL中,但状态应该更改。就像github一样。
我该怎么做?
答案 0 :(得分:2)
这样做
(function () {
angular.module('mean').config(aosOfferConfig);
function aosOfferConfig($stateProvider, $urlRouterProvider) {
$urlRouterProvider.otherwise(function ($injector, $location) {
var state = $injector.get('$state');
state.go('404_not_found', {}, { location: false });
return $location.path();
});
$stateProvider
.state('offers', {
url: '/offers/packages',
templateUrl: 'views/aosOffers/aosoffers.html',
controller: 'offersController',
controllerAs: 'packages'
})
.state('offersignup', {
url: '/offers/signup',
templateUrl: 'views/aosOffers/offerssignup.html',
controller: 'offersSignupController',
controllerAs: 'offerssignup'
})
.state('thankyou', {
url: '/offers/thankyou',
templateUrl: 'views/aosOffers/offersthankyou.html'
})
.state('404_not_found', {
template: '<h1>Notfound</h1>'
});
}
})();