Question

我正在尝试用链接替换文本。我现在使用的正则表达式替换了所有匹配，但我只想替换前两次出现。

它应该用链接替换所有出现的find me，除非它位于或标记中。

https://regex101.com/r/6R2ydW/1 http://www.phpliveregex.com/p/nLI

我当前的正则表达式：

/<(a|h[1-6])[^>]*>(?:[a-zA-Z0-9\s\'\-\.,]|(?:<(.*)>.*<\/\1>))*<\/(a|h[1-6])>(*SKIP)(*FAIL)|\b(Find Me)\b(?=[^>]*(?:<|$))/ig

我的虚拟内容：

Lorem ipsum find me and skip when 
<b>find me</b> is inside a link tag 
like this find me
<h1>find me in the title</h1>
<a href="#">here you can find me too</a>.
<h2 class="heading">Lorem Ipsum dolor find me here too</h2>
<table>
  <tr><td>Cell 1 a</td><td>Find me</td></tr>
  <tr><td>Cell 2 with find me</td><td><a href="#foo">Find me</a></td></tr>
</table>
<h3 class="heading">Duomo Di find me San Martino</h3>
<p>FIND ME as well</p>

我的PHP preg_replace：

$text = 'Lorem ipsum find me and skip when 
    <b>find me</b> is inside a link tag 
    like this find me
    <h1>find me in the title</h1>
    <a href="#">here you can find me too</a>.
    <h2 class="heading">Lorem Ipsum dolor find me here too</h2>
    <table>
      <tr><td>Cell 1 a</td><td>Find me</td></tr>
      <tr><td>Cell 2 with find me</td><td><a href="#foo">Find me</a></td></tr>
    </table>
    <h3 class="heading">Duomo Di find me San Martino</h3>
    <p>FIND ME as well</p>';

$regex = "/<(a|h[1-6])[^>]*>(?:[a-zA-Z0-9\s\'\-\.,]|(?:<(.*)>.*<\/\1>))*<\/(a|h[1-6])>(*SKIP)(*FAIL)|\b(" . preg_quote('find me') . ")\b(?=[^>]*(?:<|$))/i";

$text = preg_replace($regex, sprintf('<a href="%s">$4</a>', 'http://example.com'), $text);

希望一位程序员可以帮助我：）

Answer 1

使用（对我来说）未知$limit参数修正了它。

$text = preg_replace($regex, sprintf('<a href="%s">$4</a>', 'http://example.com'), $text, $limit = 2);

http://php.net/manual/en/function.preg-replace.php

只匹配正则表达式中的前两个出现 - PHP

1 个答案: