Question

我为我的2 UITapGestureRecognizer添加了2个函数UIImage，用于显示每个UIImage的不同图片。

因此，当我点按其中一个UIImage时，UIAlertController会显示并提供2个添加图片的选项（使用相机或使用图书馆）

但是当我添加图片时，它们都显示相同的图片（当我使用imagePickerController时

在我添加if else语句后，即使我点击了第二个if

，图片也会显示在UIImage语句中

例如：

我有2 UIImage名为imageView1.image和imageView2.image

点击我的第一个imageView1.image，UIAlertController显示选项（相机和库）我选择了库并选择了image1.jpg

选择image1.jpg后，imageView1.image和imageView2.image都显示相同的图片。

我在if else中添加func imagePickerController语句后，image1.jpg仅显示在if语句中...即使我点按了imageVIew2.image

但是，我想要的是...... 当我点按imageView1.image并选择image1.jpg时，显示image1.jpg的imageView1.image和imageView2.jpg不显示任何内容。

这是我的代码（没有其他）：

extension KUYPEP {

//pencetGambarnya1 for imageView1.image
@objc func pencetGambarnya1(tapGestureRecognizer1: UITapGestureRecognizer) {

            let imagePickerController = UIImagePickerController()
            imagePickerController.delegate = self

            let gambarDipencet1 = tapGestureRecognizer1.view as! UIImageView


            let act1 = UIAlertController(title: "Choose Image", message: nil, preferredStyle: .actionSheet)


            act1.addAction(UIAlertAction(title: "Camera", style: .default, handler: {(UIAlertAction) in
                if UIImagePickerController.isSourceTypeAvailable(.camera) {

                    imagePickerController.sourceType = .camera;

                    self.present (imagePickerController, animated: true, completion: nil)
                } else {


                    print ("Camera ruksak")

                }
            }))

            act1.addAction(UIAlertAction(title: "Library", style: .default, handler: {(UIAlertAction) in

                imagePickerController.sourceType = .photoLibrary

                self.present(imagePickerController, animated: true, completion: nil)

            }))

            act1.addAction(UIAlertAction(title: "Cancel", style: .cancel, handler: {(UIAlertAction)in}))


            self.present(act1, animated: true, completion: nil)

            print ("berhasil11")


        }



//pencetGambarnya2 for imageView2.image
    @objc func pencetGambarnya2(tapGestureRecognizer2: UITapGestureRecognizer) {



        let imagePickerController2 = UIImagePickerController()
        imagePickerController2.delegate = self

        let gambarDipencet2 = tapGestureRecognizer2.view as! UIImageView


        let act2 = UIAlertController(title: "Choose Image", message: nil, preferredStyle: .actionSheet)


        act2.addAction(UIAlertAction(title: "Camera", style: .default, handler: {(UIAlertAction) in
            if UIImagePickerController.isSourceTypeAvailable(.camera) {

                imagePickerController2.sourceType = .camera;

                self.present (imagePickerController2, animated: true, completion: nil)
            } else {


                print ("Camera ruksak")

            }
        }))

        act2.addAction(UIAlertAction(title: "Library", style: .default, handler: {(UIAlertAction) in

            imagePickerController2.sourceType = .photoLibrary

            self.present(imagePickerController2, animated: true, completion: nil)

        }))

        act2.addAction(UIAlertAction(title: "Cancel", style: .cancel, handler: {(UIAlertAction)in}))


        self.present(act2, animated: true, completion: nil)

        print ("berhasil22")

    }



    func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {

            let image1 = info[UIImagePickerControllerOriginalImage] as! UIImage
            imageView1.image = image1





        let image2 = info[UIImagePickerControllerOriginalImage] as! UIImage
        imageView2.image = image2



        picker.dismiss(animated: true, completion: nil)

        print ("Slavic Hardbass")
    }



    func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {

        picker.dismiss(animated: true, completion: nil)

    }
}

这是我的viewDidLoad

let tapGestureRecognizer1 = UITapGestureRecognizer(target: self, action: #selector(pencetGambarnya1(tapGestureRecognizer1:)))

    imageView1.isUserInteractionEnabled = true
    imageView1.addGestureRecognizer(tapGestureRecognizer1)



    let tapGestureRecognizer2 = UITapGestureRecognizer(target: self, action: #selector(pencetGambarnya2(tapGestureRecognizer2:)))

    imageView2.isUserInteractionEnabled = true
    imageView2.addGestureRecognizer(tapGestureRecognizer2)

Answer 1

创建一个名为targetImage的公共UIImage并执行以下操作，在呈现imagePickerController之前，将image1或image2的引用分配给targetImage。完成拾取图像后，只需将拾取的图像设置为targetImage。你可以在下面的代码中看到，我已经设置了targetImage = imageView1。

act1.addAction(UIAlertAction(title: "Camera", style: .default, handler: {(UIAlertAction) in
                if UIImagePickerController.isSourceTypeAvailable(.camera) {

                    imagePickerController.sourceType = .camera;
                    targetImage = imageView1
                    self.present (imagePickerController, animated: true, completion: nil)
                } else {


                    print ("Camera ruksak")

                }
            }))

对imageView2也一样，之后修改代码以设置这样的选择媒体，

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {

            let image1 = info[UIImagePickerControllerOriginalImage] as! UIImage
            targetImage.image = image1

        picker.dismiss(animated: true, completion: nil)

        print ("Slavic Hardbass")
    }

我没有对此进行测试，但这应该可行。

Answer 2

试试此代码。希望它适合你

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {

    if picker == imagePickerController
    {
         let image1 = info[UIImagePickerControllerOriginalImage] as! UIImage
         imageView1.image = image1
    }
   else
    {
        let image2 = info[UIImagePickerControllerOriginalImage] as! UIImage
        imageView2.image = image2
    }

   picker.dismiss(animated: true, completion: nil)

    print ("Slavic Hardbass")
}

Answer 3

使用此代码

在类中添加var来解决此问题

answer

感谢您的回复。

两个UIImage都显示不同的图像

3 个答案: