Question

这是文本文件，我想读取文本文件并将名称年龄和地址存储到对象中。我对该程序有疑问，对不熟悉java

name：name1 年龄：20岁地址：kokrajhar

我希望结果如下： StudenInfo [name = name1，age = 20，address = kokrajhar]

StudentInfo.java

#include <mach/mach_init.h>
#include <mach/mach_error.h>
#include <mach/mach_host.h>
#include <mach/vm_map.h>

static unsigned long long _previousTotalTicks = 0;
static unsigned long long _previousIdleTicks = 0;

// Returns 1.0f for "CPU fully pinned", 0.0f for "CPU idle", or somewhere in between
// You'll need to call this at regular intervals, since it measures the load between
// the previous call and the current one.
float GetCPULoad()
{
   host_cpu_load_info_data_t cpuinfo;
   mach_msg_type_number_t count = HOST_CPU_LOAD_INFO_COUNT;
   if (host_statistics(mach_host_self(), HOST_CPU_LOAD_INFO, (host_info_t)&cpuinfo, &count) == KERN_SUCCESS)
   {
      unsigned long long totalTicks = 0;
      for(int i=0; i<CPU_STATE_MAX; i++) totalTicks += cpuinfo.cpu_ticks[i];
      return CalculateCPULoad(cpuinfo.cpu_ticks[CPU_STATE_IDLE], totalTicks);
   }
   else return -1.0f;
}

float CalculateCPULoad(unsigned long long idleTicks, unsigned long long totalTicks)
{
  unsigned long long totalTicksSinceLastTime = totalTicks-_previousTotalTicks;
  unsigned long long idleTicksSinceLastTime  = idleTicks-_previousIdleTicks;
  float ret = 1.0f-((totalTicksSinceLastTime > 0) ? ((float)idleTicksSinceLastTime)/totalTicksSinceLastTime : 0);
  _previousTotalTicks = totalTicks;
  _previousIdleTicks  = idleTicks;
  return ret;
}

Test.java

public class StudenInfo{

    private static String name;

    private static Integer age;

    private static String address;


    public String getName() {
        return name;
    }

    public static void setName(String name) {
        StudenInfo.name = name;
    }

    public static Integer getAge() {
        return age;
    }

    public static void setAge(Integer age) {
        StudenInfo.age = age;
    }

    public static String getAddress() {
        return address;
    }

    public static void setAddress(String address) {
        StudenInfo.address = address;
    }

    @Override
    public String toString() {
        return "StudenInfo [name=" + name + ", age=" +age +", address=" + address +"]";
    }


    }

Answer 1

首先，如前面的答案所说，你不应该使用静态变量，因为它会修改所有对象的值，你最终会得到相同的值。

第二，如果你总是指望你的信息被格式化，那么你应该使用正则表达式，因为你正在进行的分割只会导致更多的错误。

这是一个如何使用它的例子：

     Pattern pattern = Pattern.compile("\\w*\\s:\\s\\w*"); // this will split on groups of information, like name : name1
        List<String> studentInfo = new ArrayList();
        Matcher matcher = pattern.matcher(test);
        while (matcher.find()) {
            studentInfo.add(matcher.group());
        }


studentInfo.get(0).substring(studentInfo.get(0).trim().lastIndexOf(" ")); // this is the name
        studentInfo.get(1).substring(studentInfo.get(1).trim().lastIndexOf(" ")); // this is the age
        studentInfo.get(2).substring(studentInfo.get(2).trim().lastIndexOf(" ")); // this is the address

从文本文件中读取并存储在对象中

1 个答案: