我正在制作一个论坛,有点练习我的技能,但我正在努力让它显示正确的东西。在这里,你看到我的代码解释了我想要的和我拥有的东西。
此代码将显示电路板列表:
<?php
$boardds = $app->get_boards();
foreach ($boardds as $board) {
if($board['url'] == $url[1]){
$actiefboardid = $board['id'];
echo '<li style="background-color:lightgray;"><a href=""'.$board['url'].'">' . $board['topic'] . '</a></li>';
} else {
echo '<li><a href="'.$board['url'].'">' . $board['topic'] . '</a></li>';
}
}
?>
之后在代码中我将显示所有&#39;主题&#39;根据我们所在的董事会,如下:
<?php
echo "<div class='tab-pane' id='activity'>";
echo "<div class='post clearfix'>";
$toppic = $app->get_topics($actiefboardid); <--- here I am displaying the records based on $actiefboardid
foreach($toppic as $topic){
echo "<div class='user-block'>";
if(file_exists('assets/images/profielfotos/'.$topic['klant_id'])) { ..... ect
现在我希望它显示类似&#34;这个董事会没有主题&#34;当没有该董事会的记录时。
答案 0 :(得分:0)
应用如下所示的count()条件: -
$toppic = $app->get_topics($actiefboardid);
if(count($toppic)>0){
foreach($topic as $topic){
//your code
}
}else{
echo "There are no topics on this board";
}
代码必须是这样的: -
<?php
$boardds = $app->get_boards();
if(isset($url[1])){
foreach ($boardds as $board) {
if($board['url'] == $url[1]){
$actiefboardid = $board['id'];
echo '<li style="background-color:lightgray;"><a href=""'.$board['url'].'">' . $board['topic'] . '</a></li>';
} else {
echo '<li><a href="'.$board['url'].'">' . $board['topic'] . '</a></li>';
}
}
}else{
echo "Please provide url 1";
}
?>
和: -
<?php
echo "<div class='tab-pane' id='activity'>";
echo "<div class='post clearfix'>";
if(isset($actiefboardid)){
$toppic = $app->get_topics($actiefboardid); <--- here I am displaying the records based on $actiefboardid
if(count($toppic) > 0){
foreach($toppic as $topic){
echo "<div class='user-block'>";
if(file_exists('assets/images/profielfotos/'.$topic['klant_id'])) { //..... ect
}
}
}
}