Question

我有一个具有不同值的动态变量

$a = (1,2,3,4,5);  
$a = (2,3,4,5,6);

我想要一个将每个数组的每个索引求和的结果

$a = (3,5,7,9,11);

while($row=mysqli_fetch_array($sql)){  
   $a = explode(',',$row['array']); //array with same variable name
}

Answer 1

您可以使用array_map：

$a = array();
while($row=mysqli_fetch_array($sql)){  
    $a = array_map(function ($x, $y) { return $x + $y; }, $a,  explode(',',$row['array']));
}
print_r($a);

假设您的代码返回

行

$row['array'] = '1,2,3,4,5';  
$row['array'] = '2,3,4,5,6';

输出将是：

Array
(
    [0] => 3
    [1] => 5
    [2] => 7
    [3] => 9
    [4] => 11
)

Answer 2

可能会低于代码将帮助您

$a = array(1,2,3,4,5,4,5);  
$b = array(2,3,4,5,6,7,3);
foreach($a as $k=>$v)
{
$temp = $a[$k]+$b[$k];
$c[] = $temp;
}
print_r($c);

具有相同变量php的数组的SUM

2 个答案: