Post方法不是在api调用中发送我的数据

时间:2018-04-24 06:33:10

标签: ios swift post httprequest swifty-json

嗨,我是swift的新手,我跟随api调用o发送数据,但它没有发送,我得到了以下回复。

已发送数据

firstName=gggg&lastName=ggg&username=fgg&password=ghh&email=ggg@gg.com&latitude=25.0710693470323&longitude=55.143004052641

响应

responseString  {"status":"error","message":"Oops!!!Something went wrong..."}

但是我可以获得所有其他验证消息,例如“用户名不能为空”。

但我尝试使用Postman它也在头文件方法上给出了与上面相同的错误信息,但后来我想出并发送了Body Method和application / x-www-form-urlencoded的形式,然后我得到了成功的响应,如下所示。 / p>

enter image description here

以下是我的API调用...请有人弄清楚我做错了什么或建议我更好的后api电话。

这是我为“/ homefeed”制作的相同API调用方法,并得到了响应,但我们不需要为此发送任何特定参数。请帮帮我。

 func addNewUser()
    {
        let url = URL(string: "https://xxxxxxxxxx.azurewebsites.net/api/addUser")!

        let firstName:String = firstnameTextFeild.text!
        let lastName:String = lastNameTxtField.text!
        let username:String = usernameTextField.text!
        let password:String = passwordTextField.text!
        let email:String = emailTextField.text!
        var request = URLRequest(url: url)
        request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
        request.httpMethod = "POST"
        let postString = "firstName=\(firstName)&lastName=\(lastName)&username=\(username)&password=\(password)&email=\(email)&latitude=\(lat)&longitude=\(long)"
        print("Sent Data -",postString)
        request.httpBody = postString.data(using: .utf8)
        /*
        do {
            request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: .prettyPrinted) // pass dictionary to nsdata object and set it as request body

        } catch let error {
            print(error.localizedDescription)
        }
       */
        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {                                                 // check for fundamental networking error
                print("error=\(String(describing: error))")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {           // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")
            }

            let responseString = String(data: data, encoding: .utf8)

            // print("responseString = \(String(describing: responseString))")
            print("responseString ", responseString ?? "resSt")


        }
        task.resume()

    }

2 个答案:

答案 0 :(得分:1)

您应该像这样传递参数:

A

答案 1 :(得分:1)

使用此代码。为您工作。

安装podfile

  

pod'Alamofire'

在ViewController中导入Alamofire

func addNewUser(){
let url = "your URL"
var param : [String : AnyObject] = [:]

param = ["firstName": firstnameTextFeild.text! as AnyObject,
         "lastName": lastNameTxtField.text! as AnyObject,
         "username": usernameTextField.text! as AnyObject,
         "password": passwordTextField.text! as AnyObject,
         "email": emailTextField.text! as AnyObject,
         "latitude": "your latitude" as AnyObject,
         "longitude": "your longitude" as AnyObject]
print(param)
Alamofire.request(url, method: .post, parameters: param, encoding: URLEncoding()).responseJSON { (response:DataResponse<Any>) in
    print(response)

    if (response.result.value != nil) {
        //your code
    }
    else{
        //your code
    }
  }
}