如何在Hibernate中修复命名查询错误(意外令牌:DAY)?

时间:2018-04-24 05:42:47

标签: java hibernate named-query

以下是查找超过90天的活动的命名查询:

"DELETE FROM PAActivity pa WHERE pa.status IN (:statusSet) AND cast(pa.datoFinish as date) < cast(DATE_SUB(current_date(), INTERVAL (:noofdays) DAY) as date)"

在编译期间,它给出了以下Hibernate异常:

ERROR 2018-04-24 11:00:07,579 o.h.h.i.a.ErrorCounter - line 1:243: unexpected token: DAY
ERROR 2018-04-24 11:00:07,579 o.h.h.i.a.ErrorCounter - line 1:243: unexpected token: DAY
line 1:243: unexpected token: DAY
    at org.hibernate.hql.internal.antlr.HqlBaseParser.primaryExpression(HqlBaseParser.java:876)
    at org.hibernate.hql.internal.antlr.HqlBaseParser.atom(HqlBaseParser.java:3472)
    at org.hibernate.hql.internal.antlr.HqlBaseParser.unaryExpression(HqlBaseParser.java:3250) .
.
.
.
.
WARN  2018-04-24 11:00:07,641 o.h.h.i.a.HqlParser - HHH000203: processEqualityExpression() : No expression to process!
ERROR 2018-04-24 11:00:08,094 o.h.i.SessionFactoryImpl - HHH000177: Error in named query: deletePAActivityByProcessIDs
org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: DAY near line 1, column 243 [DELETE FROM fn.gover.model.PAActivity pa WHERE pa.status IN (:statusSet) AND cast(pa.datoFinish as date) < cast(DATE_SUB(current_date(), INTERVAL (:noofdays) DAY) as date)]
    at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:54)
    at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:47)

1 个答案:

答案 0 :(得分:1)

我认为问题是HQL不支持INTERVAL

您可以通过两种方式解决问题。 第一 - RestrictionCriteria

Calendar c = Calendar.getInstance();
c.add(Calendar.DAY_OF_YEAR, -90); 
Criteria criteria = session.createCriteria(Yourclass.class);
criteria.add(Restrictions.ge("datoFinish", c.getTime());
List results = criteria.list();

或者只需更改您的查询:

AND cast(pa.datoFinish as date) < cast(:dateMinus90 as date)

并将参数设置为日历

的结果
.setParameter("dateMinus90", c.getTime())

第二种方式是继承方言类并注册sql函数。例如对于Oracle。

public class MyOracleDialect extends Oracle10gDialect {
    @Override
    protected void registerFunctions() {
        super.registerFunctions();
        registerFunction("sub_days", new SQLFunctionTemplate(StandardBasicTypes.DATE, " date_sub(?1, INTERVAL ?2 DAY)"));
    } }

然后在hibernate道具中你应该使用这种方言。但我认为这不是最好的方式。