Question

我对SQL Server完全不熟悉，任何人都可以指导我查询它对我有用。

我需要像这个例子中那样生成排名：

Report No               Rank 
----------------------------
18  3229                 1
89-0119-87               2
180261292                3
180261292                3
18  3107                 4
18A 7     A06            5
T18002415                6
T18002415                6
T18002415                6
0000000018-519           7
0000000018-519           7
0000000018-519           7
0000000018-519           7
0000000018-655           8
000000018-1002           9
000000018-1002           9
000000018-1002           9
000000018-5712           10

如果我使用

生成排名

DENSE_RANK() OVER(ORDER BY ReportNo DESC)

然后我没有得到所需的输出。你能指导我吗？如何在上面的例子中生成排名？

Answer 1

我无法看到如何订购报告编号的逻辑。按照自定义顺序，创建包含所需订单anotherTable，Report No的{{1}}（临时表或表变量）。

Rank

然后

Report No           Rank 
18  3229                 1
89-0119-87               2
180261292                3
18  3107                 4
18A 7     A06            5
T18002415                6
0000000018-519           7
0000000018-655           8
000000018-1002           9
000000018-5712           10

Answer 2

试试这个：

@RequestMapping(value="/upload",method=RequestMethod.POST)
public ModelAndView upload(@RequestParam("file") CommonsMultipartFile file,HttpSession session) throws IOException
{
    String path =  session.getServletContext().getRealPath("/");
    String filename=file.getOriginalFilename();
    ImagePOJO pojo = new ImagePOJO();
    byte barr[]=file.getBytes();    


    pojo.setPath(path);
    pojo.setFilename(filename);

    //String q = pojo.setPath(path)+"/"+pojo.setFilename(filename); 

    String w = pojo.getPath()+""+pojo.getFilename();
    //System.out.println(Arrays.toString(barr));


    System.out.println(path+" "+filename);

    System.out.println(w);


    BufferedOutputStream bout;
    try {
        bout = new BufferedOutputStream(new FileOutputStream(path+"/"+filename));


        Object o = bout;
        bout.write(barr);
        bout.flush();
        bout.close();

    } catch (FileNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }[enter image description here][1]

<强>输出：

DECLARE @Tab TABLE(Report_No VARCHAR(100))

INSERT INTO @Tab VALUES('18  3229')
INSERT INTO @Tab VALUES('89-0119-87')
INSERT INTO @Tab VALUES('180261292')
INSERT INTO @Tab VALUES('180261292')
INSERT INTO @Tab VALUES('18  3107')
INSERT INTO @Tab VALUES('18A 7     A06')
INSERT INTO @Tab VALUES('T18002415')
INSERT INTO @Tab VALUES('T18002415')
INSERT INTO @Tab VALUES('T18002415')
INSERT INTO @Tab VALUES('0000000018-519')
INSERT INTO @Tab VALUES('0000000018-519')
INSERT INTO @Tab VALUES('0000000018-519')
INSERT INTO @Tab VALUES('0000000018-519')
INSERT INTO @Tab VALUES('0000000018-655')
INSERT INTO @Tab VALUES('000000018-1002')
INSERT INTO @Tab VALUES('000000018-1002')
INSERT INTO @Tab VALUES('000000018-1002')
INSERT INTO @Tab VALUES('000000018-5712')

SELECT *
    ,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RN
INTO #temp
FROM @Tab T1

SELECT T1.Report_No
    ,SUM(CASE WHEN T1.Report_No = T2.Report_No THEN 0 ELSE 1 END) OVER(ORDER BY T1.rn)[Rank]
FROM #temp T1
LEFT JOIN #temp T2 ON T1.rn = T2.rn+1

DROP TABLE #temp

Answer 3

使用分组依据：

WITH data as (
    SELECT '18  3229' col1 UNION ALL
    SELECT '89-0119-87' UNION ALL
    SELECT '180261292' UNION ALL
    SELECT '180261292' UNION ALL
    SELECT '18  3107' UNION ALL
    SELECT '18A 7     A06' UNION ALL
    SELECT 'T18002415' UNION ALL
    SELECT 'T18002415' UNION ALL
    SELECT 'T18002415' UNION ALL
    SELECT '0000000018-519' UNION ALL
    SELECT '0000000018-519' UNION ALL
    SELECT '0000000018-519' UNION ALL
    SELECT '0000000018-519' UNION ALL
    SELECT '0000000018-655' UNION ALL
    SELECT '000000018-1002' UNION ALL
    SELECT '000000018-1002' UNION ALL
    SELECT '000000018-1002' UNION ALL
    SELECT '000000018-5712'), 
data_with_rownumber as (
    SELECT *, row_number() over (order by (SELECT 1)) rownum from data
), grouped as (
    SELECT col1, min(rownum) rank from data_with_rownumber group by col1)
select d.col1, DENSE_RANK() over (order by rank) from data d inner join grouped gr on d.col1 = gr.col1

生成DENSE_RANK（）而不使用order by子句 - SQL Server

3 个答案: