Question

我正在尝试创建一个网站来上传和下载任何类型的文件。首先，我创建了一个名为upload的数据库，这是表的代码：

CREATE TABLE IF NOT EXISTS `files` ( `id` int(11) NOT NULL AUTO_INCREMENT,
        `name` varchar(200) NOT NULL,
        `type` varchar(30) NOT NULL,
        `size` int(11) NOT NULL,
        `content` mediumblob NOT NULL,
        PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2;

这是我的PHP代码，用于上传文件：

<?php 

if (isset($_POST['upload']) && $_FILES['userfile']['size'] > 0) {
    $fileName = $_FILES['userfile']['name'];
    $tmpName = $_FILES['userfile']['tmp_name'];
    $fileSize = $_FILES['userfile']['size'];
    $fileType = $_FILES['userfile']['type'];
    $fp = fopen($tmpName, 'r');
    $content = fread($fp, filesize($tmpName));
    $content = addslashes($content);
    fclose($fp);

    if (!get_magic_quotes_gpc()) {
        $fileName = addslashes($fileName);
    }

    $conn = mysqli_connect("localhost","root","","upload");
    $query = "INSERT INTO files (name, size, type, content ) VALUES ('$fileName', '$fileSize', '$fileType', '$content')";
    mysqli_query($conn,$query) or die('Error, query failed');
    $_SESSION['submit']='true'; 

    //echo "
    //File $fileName uploaded
    //"; 

    header('Location: '.$_SERVER['PHP_SELF'].'?1');
    $conn -> close();
}

?>

当我尝试下载时，一切正常，但是当我打开文件时它已损坏，我不明白为什么。这是HTML页面中使用的代码。我试图在一个简单的页面中使用PHP脚本，它的工作原理。但是当我将它添加到我的网站时，它不起作用。

<?php

$conn = mysqli_connect("localhost","root","","upload");
if (isset($_GET['id'])) { // se l'id esiste allora prendi il file dal database
    $id = $_GET['id'];
    $query = "SELECT name, type, size, content FROM files WHERE id = $id";
    $result = mysqli_query($conn,$query) or die('Error, query failed');
    list($name, $type, $size, $content) =
    mysqli_fetch_array($result);
    header("Content-length: $size");
    header("Content-type: $type");
    header("Content-Disposition: attachment; filename=$name");
    echo $content; exit;
}

$query = "SELECT files.id, files.name FROM files";
$result = mysqli_query($conn,$query) or die('Error, query failed');

if (mysqli_num_rows($result) == 0) {

    echo "<p>Il tuo database e' vuoto !</p>";
} else {
    echo "<div class='box alt'>";
    echo "<div class='row uniform 50%'>";
    while (list($id, $name) = mysqli_fetch_array($result)) {

?>

<div class="4u">
    <span class="image fit"><img src="images/pic02.jpg" alt="" /></span><h3><?php echo $name; ?></h3>
    <ul class="actions">
        <li><a href="index.php?id=<?php echo $id;?>" class="button">Download</a></li>
    </ul>
</div>

<?php }} ?>

使用php从mysqli数据库下载一个看似损坏的文件

0 个答案: