Question

我想编辑给定文件address.txt中的手机号码，但是当我输入了错误的手机号码时，如果我在address.txt文件中有三个条目，则此代码会多次打印“手机号码未找到”，那么它将打印三次“未找到手机号码“。我想打印一次我的其他声明帮助吗？

def editContact():
        obj2 = open("address.txt","r")  
        output = []
        number = raw_input("Enter 1 for edit email id and Enter 2 for edit phone number : ")
        if(number=="1"):
                old_number=raw_input("Enter old phone number  : ")
                for line in obj2.readlines():
                    if old_number in line: 
                           print line             
                           new_number=raw_input("Enter new phone number : ")
                           obj2 = open("address.txt","r")
                           aa=obj2.read()
                           s = re.sub(old_number, new_number, aa)    
                           obj1 = open("address.txt","w")
                           obj1.writelines(s)
                           print "Number Edit sucessfully"
                    else:
                           print "Mobile number not found"  
        else:
                 print "Incorrect choice"

输出

Mobile number not found
Mobile number not found
Mobile number not found

所需的输出：

 Mobile number not found

Answer 1

根据我的理解：您的文件有3个条目（3个电话号码），如果找不到输入条目，您只想打印一次。

import re

def editContact():
    obj2 = open("address.txt", "r")
    output = []
    number = raw_input("Enter 1 for edit email id and Enter 2 for edit phone number : ")
    if (number == "1"):

        old_number = raw_input("Enter old phone number  : ")

        for line in obj2.readlines():
            if old_number in line:
                print line
                new_number = raw_input("Enter new phone number : ")
                obj2 = open("address.txt", "r")
                aa = obj2.read()
                s = re.sub(old_number, new_number, aa)
                obj1 = open("address.txt", "w")
                obj1.writelines(s)
                print "Number Edit sucessfully"
                break

        else:
            print "EOF Reached, number not found!"
    else:
        print "Incorrect choice"

editContact()

输出是： Enter 1 for edit email id and Enter 2 for edit phone number : 1 Enter old phone number : 123 EOF Reached, number not found!

Answer 2

我建议使用一个布尔变量。在这种情况下，present是在函数的第6行引入的布尔变量。

def editContact():
        obj2 = open("address.txt","r")  
        output = []
        number = raw_input("Enter 1 for edit email id and Enter 2 for edit phone number : ")
        if(number=="1"):
                old_number=raw_input("Enter old phone number  : ")
                present = False # this will check if number is present or not
                for line in obj2.readlines():
                    if old_number in line: 
                           present = True # since number is present make it True
                           print line             
                           new_number=raw_input("Enter new phone number : ")
                           obj2 = open("address.txt","r")
                           aa=obj2.read()
                           s = re.sub(old_number, new_number, aa)    
                           obj1 = open("address.txt","w")
                           obj1.writelines(s)
                           print "Number Edit sucessfully"

                #After every line in text file is parsed check its value  
                if present == False:
                   print "Mobile number not found"  
        else:
                 print "Incorrect choice"

Answer 3

def editContact():
        obj2 = open("address.txt","r")  
        output = []
        number = raw_input("Enter 1 for edit email id and Enter 2 for edit phone number : ")
        if(number=="1"):
            old_number=raw_input("Enter old phone number  : ")
            for line in obj2.readlines():
                if old_number in line: 
                    print line             
                    new_number=raw_input("Enter new phone number : ")
                    obj2 = open("address.txt","r")
                    aa=obj2.read()
                    s = re.sub(old_number, new_number, aa)    
                    obj1 = open("address.txt","w")
                    obj1.writelines(s)
                    print "Number Edit sucessfully"
                    break
            else:
                print "Mobile number not found"  
        else:
            print "Incorrect choice"

将else语句移出循环将解决问题。此外，break语句中的if是必要的，否则它也会重复。

else语句打印多次？

3 个答案: