Question

我有一个模型对象User，另一个模型对象是Picture。

 "user": {
            "id": 1,
            "email": "abc.k@gmail.com",
     "user_profile_photo": {
                "id": 997,
                "user_id": 1,
                "photo_url": "https://newproduction.s3.amazonaws.com/profile_image/RkUJAczv5nWpUyFTgyTgMLChR.jpeg",
                           }   
         }

我有两个模型类，一个是用户，另一个是用户内的图片。我在userdefault中保存模型用户，如下所示

    //Get Response
    loginResponseObj = Mapper<LoginResponse>().map(JSONObject:(response.result.value))

   //Save user Details
   let userData = loginResponseObj.user!
        let data  = NSKeyedArchiver.archivedData(withRootObject: userData)
        UserDefaults.standard.set(data, forKey:"user")

当我尝试从userdefaults获取数据时，我正在获取用户模型，但内部细节为零。

从userdefault获取Userdetails代码位于

之下

guard let data = UserDefaults.standard.object(forKey: "user") as? Data
            else
        {
            return UserModel()

        }
        return (NSKeyedUnarchiver.unarchiveObject(with: data) as? UserModel)!

此返回**<ABC.User: 0x7f84f740c440>**

但是当我尝试从用户获取图片时，它返回nil

在用户模型

中

 class User:NSObject,Mappable,NSCoding{

 var email: String?
 var picture: Picture?

required init?(coder aDecoder: NSCoder) {
        self.email = aDecoder.decodeObject(forKey: "email") as? String
    }
    func initWithCoder(aDecoder:NSCoder) -> UserModel
    {
        self.email = aDecoder.decodeObject(forKey: "email") as? String

        return self
    }

    func encode(with aCoder: NSCoder) {
        aCoder.encode(email, forKey: "email")
    }

} 在图片模型

中

class Picture:Mappable,NSCoding{

    var id: String?
    var photoURL: String?

    required init?(coder aDecoder: NSCoder) {
            self.id = aDecoder.decodeObject(forKey: "id") as? String
            self.photoURL = aDecoder.decodeObject(forKey: "photoURL") as? String
        }
        func initWithCoder(aDecoder:NSCoder) -> Picture
        {
            self.id = aDecoder.decodeObject(forKey: "id") as? String
            self.photoURL = aDecoder.decodeObject(forKey: "photoURL") as? String

            return self
        }

        func encode(with aCoder: NSCoder) {
            aCoder.encode(id, forKey: "id")


 }

} 注意：我使用的是MVVM模式和对象映射器

那么，我怎样才能获得用户的全部细节，包括photo_url（User.Picture.photo_url）？

Answer 1

在用户模型

中

[TestClass]
public class ExampleTest {
    public interface IInterface {
        void Method(string p, out StringBuilder builder);
    }

    public class MyClass {
        private IInterface p;

        public MyClass(IInterface p) {
            this.p = p;
        }

        public void Act() {
            var builder = new StringBuilder();
            p.Method("String", out builder);
        }
    }

    [TestMethod]
    public void Should_Ignore_Out() {
        //Arrange
        var mock = new Mock<IInterface>();
        var sut = new MyClass(mock.Object);

        //Act
        sut.Act();

        //Assert
        var builder = new StringBuilder();
        mock.Verify(x => x.Method("String", out builder), Times.Once);
    }
}

在图片模型

中

class User:NSObject,Mappable,NSCoding{

 var email: String?
 var picture: Picture?

required init?(coder aDecoder: NSCoder) {
        self.email = aDecoder.decodeObject(forKey: "email") as? String
        self.picture = aDecoder.decodeObject(forKey: "picture") as? Picture
    }
    func initWithCoder(aDecoder:NSCoder) -> UserModel
    {
        self.email = aDecoder.decodeObject(forKey: "email") as? String
        self.picture = aDecoder.decodeObject(forKey: "picture") as? Picture
        return self
    }

    func encode(with aCoder: NSCoder) {
        aCoder.encode(email, forKey: "email")
        aCoder.encode(picture, forKey: "picture")
    }
}

从用户默认值中获取详细信息

class Picture: NSObject,Mappable,NSCoding {

var id: String?
var photoURL: String?

required init?(coder aDecoder: NSCoder) {
    self.id = aDecoder.decodeObject(forKey: "id") as? String
    self.photoURL = aDecoder.decodeObject(forKey: "photoURL") as? String
}
func initWithCoder(aDecoder:NSCoder) -> Picture
{
    self.id = aDecoder.decodeObject(forKey: "id") as? String
    self.photoURL = aDecoder.decodeObject(forKey: "photoURL") as? String

    return self
}

func encode(with aCoder: NSCoder) {
    aCoder.encode(id, forKey: "id")
    aCoder.encode(photoURL, forKey: "photoURL")
}

上面的代码将返回用户模型使用此模型访问其变量

guard let data = UserDefaults.standard.object(forKey: "user") as? Data
            else
        {
            return User()

        }
        return (NSKeyedUnarchiver.unarchiveObject(with: data) as? User)!

使用userdefault保存并获取Model类的详细信息

1 个答案: