我有一个JSON内容为
[{
"LocalObservationDateTime": "2018-04-23T08:10:00+05:00",
"EpochTime": 1524453000,
"WeatherText": "Sunny",
"WeatherIcon": 1,
"IsDayTime": true,
"Temperature": {
"Metric": {
"Value": 29.6,
"Unit": "C",
"UnitType": 17
},
"Imperial": {
"Value": 85.0,
"Unit": "F",
"UnitType": 18
}
},
"MobileLink": "http://m.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us",
"Link": "http://www.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us"
}]
我的课程处理此内容如下:
class AccuWeather
{
public class RootObject
{
public Class1[] Property1 { get; set; }
}
public class Class1
{
public DateTime LocalObservationDateTime { get; set; }
public int EpochTime { get; set; }
public string WeatherText { get; set; }
public int WeatherIcon { get; set; }
public bool IsDayTime { get; set; }
public Temperature Temperature { get; set; }
public string MobileLink { get; set; }
public string Link { get; set; }
}
我刚尝试通过C#中的以下代码片段反序列化此内容:
private AccuWeather.RootObject Parse_A(string targetURI)
{
Uri uri = new Uri(targetURI);
var webRequest = WebRequest.Create(uri);
WebResponse response = webRequest.GetResponse();
AccuWeather.RootObject wUData = null;
try
{
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
var responseData = streamReader.ReadToEnd();
// if you want all the "raw data" as a string
// just use: responseData.ToString()
wUData = JsonConvert.DeserializeObject<AccuWeather.RootObject<Class1>>(responseData);
}
}
catch (Exception e)
{
MessageBox.Show(e.Message);
}
return wUData;
}//completed
我不确定这是反序列化JSON内容的正确有效方法。在这种情况下,任何人都能提供一些关于最佳实践的详细信息吗 提前感谢任何帮助!
答案 0 :(得分:1)
您也可以使用.NET动态,例如
var json = @"[{""LocalObservationDateTime"": ""2018-04-23T08:10:00+05:00"",
""EpochTime"": 1524453000,
""WeatherText"": ""Sunny"",
""WeatherIcon"": 1,
""IsDayTime"": true,
""Temperature"": {
""Metric"": {
""Value"": 29.6,
""Unit"": ""C"",
""UnitType"": 17
},
""Imperial"": {
""Value"": 85.0,
""Unit"": ""F"",
""UnitType"": 18
}
},
""MobileLink"": ""http://m.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us"",
""Link"": ""http://www.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us""
}]";
dynamic accuWeatherResp = JArray.Parse(json);
if (accuWeatherResp.Count == 0)
{
Console.WriteLine("Response is Empty");
return;
}
dynamic weather = accuWeatherResp[0];
if (weather != null)
{
Console.WriteLine("Observation time: {0:s} Weather: {1}, Temperature: {2: 0.0} °C", weather.LocalObservationDateTime, weather.WeatherText, weather.Temperature.Metric.Value);
}
答案 1 :(得分:0)
有一个名为quicktype.io的页面,您可以在其中粘贴JSON并接收C#类和相应的转换器代码:
using System.Globalization;
using Newtonsoft.Json;
using Newtonsoft.Json.Converters;
public partial class Welcome
{
[JsonProperty("LocalObservationDateTime")]
public DateTimeOffset LocalObservationDateTime { get; set; }
[JsonProperty("EpochTime")]
public long EpochTime { get; set; }
[JsonProperty("WeatherText")]
public string WeatherText { get; set; }
[JsonProperty("WeatherIcon")]
public long WeatherIcon { get; set; }
[JsonProperty("IsDayTime")]
public bool IsDayTime { get; set; }
[JsonProperty("Temperature")]
public Temperature Temperature { get; set; }
[JsonProperty("MobileLink")]
public string MobileLink { get; set; }
[JsonProperty("Link")]
public string Link { get; set; }
}
public partial class Temperature
{
[JsonProperty("Metric")]
public Imperial Metric { get; set; }
[JsonProperty("Imperial")]
public Imperial Imperial { get; set; }
}
public partial class Imperial
{
[JsonProperty("Value")]
public double Value { get; set; }
[JsonProperty("Unit")]
public string Unit { get; set; }
[JsonProperty("UnitType")]
public long UnitType { get; set; }
}
public partial class Welcome
{
public static Welcome[] FromJson(string json) => JsonConvert.DeserializeObject<Welcome[]>(json, QuickType.Converter.Settings);
}
public static class Serialize
{
public static string ToJson(this Welcome[] self) => JsonConvert.SerializeObject(self, QuickType.Converter.Settings);
}
internal static class Converter
{
public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
{
MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
DateParseHandling = DateParseHandling.None,
Converters = {
new IsoDateTimeConverter { DateTimeStyles = DateTimeStyles.AssumeUniversal }
},
};
}