如何获取子列表的N个元素?假设我想为每个父母分别生两个孩子。
public class Program
{
static void Main(string[] args)
{
var data = new List<Parent>()
{
new Parent()
{
Id = 1,
Name = "ParentName1",
Children = new List<Child>()
{
new Child() { Id = 1, Name = "ChildName1"},
new Child() { Id = 2, Name = "ChildName2"},
new Child() { Id = 3, Name = "ChildName3"},
new Child() { Id = 4, Name = "ChildName4"},
new Child() { Id = 5, Name = "ChildName5"},
}
},
new Parent()
{
Id = 2,
Name = "ParentName2",
Children = new List<Child>()
{
new Child() { Id = 6, Name = "ChildName6"},
new Child() { Id = 7, Name = "ChildName7"},
new Child() { Id = 8, Name = "ChildName8"},
new Child() { Id = 9, Name = "ChildName9"},
new Child() { Id = 10, Name = "ChildName10"},
}
}
};
// Get only 2 child elements for parent
var filteredData = data.Where(x => x.Children.Count >= 2)
.ToList();
foreach (var filteredParent in filteredData)
{
Console.WriteLine($"Parent {filteredParent.Id} with {filteredParent.Children.Count} children.");
}
Console.ReadKey();
}
}
public class Parent
{
public int Id { get; set; }
public string Name { get; set; }
public List<Child> Children { get; set; }
}
public class Child
{
public int Id { get; set; }
public string Name { get; set; }
public Parent Parent { get; set; }
}
答案 0 :(得分:1)
一种方法是对结果选择器和List<T>
的{{1}}方法使用多语句lambda表达式:
RemoveRange
正如Flater评论的那样,最好只返回父亲的浅拷贝,只有前两个孩子。这样您的查询就不会更改源数据:
var query = data.Select
(
p =>
{
p.Children.RemoveRange(2, p.Children.Count - 2);
return p;
}
);