尝试使用Codable编写一个简单的Swift 4.1
来解析json
。
我有struct
这样:
struct GameCharacter : Codable {
var name : String
var weapons : [Weapon]
enum CodingKeys : String, CodingKey {
case name
case weapons
}
init(from decoder: Decoder) {
do {
let container = try decoder.container(keyedBy: CodingKeys.self)
self.name = try container.decode(String.self, forKey: .name)
let weaponsContainer = try container.nestedContainer(keyedBy: Weapon.CodingKeys.self, forKey: .weapons)
self.weapons = try weaponsContainer.decode([Weapon].self, forKey: .weapons)
} catch let error {
print("error: \(error)")
fatalError("error is \(error)")
}
}
}
以及其他类似内容:
struct Weapon : Codable {
var name : String
enum CodingKeys : String, CodingKey {
case name
}
init(from decoder: Decoder) {
do {
let container = try decoder.container(keyedBy: CodingKeys.self)
self.name = try container.decode(String.self, forKey: .name)
} catch let error {
print("error: \(error)")
fatalError("error is \(error)")
}
}
}
我还有一个struct
这样的包装器:
struct Game : Codable {
var characters : [GameCharacter]
enum CodingKeys : String, CodingKey { case characters }
}
json数据如下所示:
{
"characters" : [{
"name" : "Steve",
"weapons" : [{
"name" : "toothpick"
}]
}]
}
但是,我总是收到typeMismatcherror错误:
错误:typeMismatch(Swift.Dictionary, Swift.DecodingError.Context(codingPath:[CodingKeys(stringValue: “characters”,intValue:nil),_ JSONKey(stringValue:“Index 0”, intValue:0)],debugDescription:“预计要解码 字典却找到了一个数组。“,underlyingError: 无))
在这一行:
let weaponsContainer = try container.nestedContainer(keyedBy: Weapon.CodingKeys.self, forKey: .weapons)
我不确定问题是什么,因为我(在我看来)要求提供一系列武器,但它认为我正在寻找一本字典。
想知道是否有人对我遗失的内容有任何见解。
答案 0 :(得分:3)
nestedContainers
- 例如将weapons
对象解码为Game
结构 - 这是不是这种情况,因为你声明了所有嵌套的结构。
要解码JSON,您可以省略所有CodingKeys和初始值设定项,利用Codable
的魔力,这就足够了:
struct Game : Codable {
let characters : [GameCharacter]
}
struct GameCharacter : Codable {
let name : String
let weapons : [Weapon]
}
struct Weapon : Codable {
let name : String
}
并将其命名为
do {
let result = try JSONDecoder().decode(Game.self, from: data)
print(result)
} catch { print(error) }
答案 1 :(得分:0)
替换您的结构,不需要任何自定义初始值设定项
import Foundation
struct Weapon: Codable {
let characters: [Character]
}
struct Character: Codable {
let name: String
let weapons: [WeaponElement]
}
struct WeaponElement: Codable {
let name: String
}
并创建
extension Weapon {
init(data: Data) throws {
self = try JSONDecoder().decode(Weapon.self, from: data)
}
现在只是
let weapon = try Weapon(json)
答案 2 :(得分:0)
试试这个
let string = """
{
"characters" : [{
"name" : "Steve",
"weapons" : [{
"name" : "toothpick"
}]
}]
}
"""
struct GameCharacter: Codable {
let characters: [Character]
}
struct Character: Codable {
let name: String
let weapons: [Weapon]
}
struct Weapon: Codable {
let name: String
}
let jsonData = string.data(using: .utf8)!
let decodr = JSONDecoder()
let result = try! decodr.decode(GameCharacter.self, from: jsonData)
let weapon = result.characters.flatMap {$0.weapons}
for weaponname in weapon {
print(weaponname.name) //Output toothpick
}
答案 3 :(得分:0)
我有同样的问题,JSONDecoder()
仅解码JSON的第一级,然后我用从Codable
扩展的类的主体中注释了这些方法来解决此问题。
public class Response<T:Codable> : Codable {
public let data : T?
//commented this two function and my problem Solved <3
// enum CodingKeys: String, CodingKey {
// case data
// }
// required public init(from decoder: Decoder) throws {
// data = try T(from: decoder)
// }
}