我正在尝试将我的循环写入文本文件,但它会将其写入控制台并将txt文件留空。
#include <iostream>
#include <vector>
#include <string.h>
#include <iostream>
#include <vector>
#include <fstream>
using namespace std;
void Crack(string password, vector<char> Chars)
{
cout<<"PASSWORD TO CRACK: "<<password<<endl;
int n = Chars.size();
int i = 0;
while(true)
{
i++;
int N = 1;
for(int j=0;j<i;j++)N*=n;
for(int j=0;j<N;j++)
{
int K = 1;
string crack = "";
for(int k=0;k<i;k++)
{
crack += Chars[j/K%n];
K *= n;
}
cout<< "Testing PASS: "<<crack<<" "<<"against " <<password<<endl;
if(password.compare(crack) == 0){
cout<<"Cracked password: "<<crack<<endl;
return;
}
}
}
}
int main()
{
ofstream myfile;
myfile.open ("pass.txt");
vector<char> Chars;
for(char c = '0';c<='z';c++){
if(islower(c) || isdigit(c))Chars.push_back(c);
}
Crack("zzzzzzzzzzzzzzzzzz", Chars);
myfile.close();
}
添加了完整的代码 我希望它将每个输入写入文本文档的新行,但无论我在哪里尝试添加
myfile << c;
它给了我奇怪的输出并且没有写入文本文件
答案 0 :(得分:0)
这是对问题的递归看法,可能更简单,您可以适应。值得注意的是,无论您选择哪种方法,此问题都需要检查26 ** 18个不同的密码,这需要很长时间。也许可以用更短的密码试试。
#include <iostream>
#include <fstream>
using namespace std;
ofstream myfile("pass.txt");
void Crack(string password, string crack, string buffer)
{
if (crack.size() == password.size()){
myfile << "Testing PASS: " << crack << " " << "against " << password << endl;
if (password.compare(crack) == 0){
myfile << "Cracked password: " << crack << endl;
}
}
else{
for (int i = 0; i < buffer.size(); i++){
Crack(password, crack+buffer[i], buffer);
}
}
}
int main()
{
string Chars = "";
for(char c = '0';c<='z';c++){
if(islower(c) || isdigit(c))
Chars+=c;
}
Crack("zzzzz","", Chars);
}