Question

我一直在尝试用Python绘制分形壳，我必须输入大小和级别的数量。每次我尝试实现代码时都会出现错误。我已经尝试过研究如何在Python中绘制一个shell，看看我能修复什么，但我似乎找不到任何有用的东西。对此的任何帮助都会很棒。

这是我到目前为止的代码：

  import math
  import turtle
  from turtle import* 

  turtle = turtle.Turtle()
  t= turtle
  t.speed(1000)
  print("MENU")
  def main():
      print ("1. Polygon Fractal")
      print("2. Fractal Shell")
      print("3. Snowflake")
      print("4. Fractal Tree")
      print("5. Exit")
      x=input("Please select a number")

      if x=="1":
          z=input("Please input the number of sides")
          a=input("Please input length")
          polygon(int(z),int(a))

      if x=="2":
          f=input("Please input a size")
          j=input("Please input a level")
          fractalshell(int(f),int(j))

      if x=="3":
          b=input("Please input a length")
          snowflake(int(b))

      if x=="4":
          fractaltree()

      if x=="5":
          t.hideturtle()
          done()

  def polygon(n,l):
      f = (n - 2) * 180/n
      for i in range(n):
          t.forward(l)
          t.right(180 - f)


  def fractalshell(size, level):
      def curve(size):
          t.right(45)
          for curve in range(0.1 *(size)):
              t.forward(0.1*(size))
              t.right(15)
          t.right(170)
          for curve in range(0.12*(size)):
              t.forward(0.1*(size))
              t.left(15)
      if (level > 0):        
          t.forward(size)
          curve(size)
          t.right(45)
          fractalshell = (0.93 * (size), level - 1)'

以下是不断出现的错误：

  Traceback (most recent call last):
    File "/Users/isabelavaldes/Dropbox/Recursion.py", line 113, in <module>
      main()
    File "/Users/isabelavaldes/Dropbox/Recursion.py", line 27, in main
      fractalshell(int(f),int(j))
    File "/Users/isabelavaldes/Dropbox/Recursion.py", line 59, in 
  fractalshell
      curve(size)
    File "/Users/isabelavaldes/Dropbox/Recursion.py", line 50, in curve
      for curve in range(0.1 *(size)):
  TypeError: 'float' object cannot be interpreted as an integer

Answer 1

你的问题似乎与Python语法比Fractal Shell更相关。例如，您不清楚预期如何工作：

fractalshell = (0.93 * (size), level - 1)'

其中fractalshell是我们所处的函数的名称，这似乎是对它的递归调用，但不是。我将您的代码重新设计为可以运行的代码（以及更多MVCE）：

from turtle import Turtle, Screen

def fractalshell(size, level):

    def curve(size):
        turtle.right(45)

        for step in range(int(10 * size)):
            turtle.forward(0.1 * step)
            turtle.right(15)

        turtle.right(170)

        for step in range(int(12 * size)):
            turtle.forward(0.8333 * step)
            turtle.left(15)

    if level > 0:
        turtle.forward(size)
        curve(size)
        turtle.right(45)
        fractalshell(0.93 * size, level - 1)

screen = Screen()

turtle = Turtle()
turtle.speed('fastest')

f = input("Please input a size: ")
j = input("Please input a level: ")

fractalshell(int(f), int(j))

turtle.hideturtle()

screen.mainloop()

它目前产生有趣的形状，但我不是他们想要的：

<强> INPUT

Please input a size: 5
Please input a level: 3

Python龟的分形壳

1 个答案: