Question

我有一张表@tbl_price，如此：

declare @tbl_price table ([date] date, stockid varchar(50), price float)

insert into @tbl_price ([date], stockid, price)
values ('2018-03-01', 10001, 24.8),
       ('2018-03-02', 10001, 26.2),
       ('2018-03-03', 10001, 27.8),
       ('2018-03-04', 10001, 28.8),
       ('2018-03-05', 10001, 21.8),
       ('2018-03-06', 10001, 23.8),
       ('2018-03-01', 20003, 30.89),
       ('2018-03-02', 20003, 33.00),
       ('2018-03-03', 20003, 34.8),
       ('2018-03-04', 20003, 34.2),
       ('2018-03-05', 20003, 33.8),
       ('2018-03-06', 20003, 43.8)

我需要进行动态旋转以显示如下输出：

date                    10001        20003
-------------------------------------------
2018-03-01              24.8         30.89

Answer 1

如果您可以使用临时表或真实表而不是表变量，则此查询应该可以很好地为您工作。它将动态返回列表中每个股票价格的新列。

CREATE TABLE #tbl_price
(
    [date]          DATE,
    stockid         VARCHAR(50),
    price           FLOAT
);

INSERT INTO #tbl_price
(
    [date],
    stockid,
    price
) VALUES
('2018-03-01',10001,24.8),
('2018-03-02',10001,26.2),
('2018-03-03',10001,27.8),
('2018-03-04',10001,28.8),
('2018-03-05',10001,21.8),
('2018-03-06',10001,23.8),
('2018-03-01',20003,30.89),
('2018-03-02',20003,33.00),
('2018-03-03',20003,34.8),
('2018-03-04',20003,34.2),
('2018-03-05',20003,33.8),
('2018-03-06',20003,43.8);

DECLARE @Stocks     NVARCHAR(MAX);
DECLARE @Query      NVARCHAR(MAX);

SET @Stocks =
    STUFF
    (
        (
            SELECT DISTINCT ',' + QUOTENAME(stockid) 
            FROM #tbl_price
            FOR XML PATH(''), TYPE
        ).value('.', 'NVARCHAR(MAX)'),
        1,
        1,
        ''
    );

SET @Query =
    'SELECT date, ' + @Stocks +
    ' FROM 
    (
        SELECT
            date,
            stockid,
            price
        FROM #tbl_price
    ) x
    PIVOT 
    (
      MAX(price)
      FOR stockid IN (' + @Stocks + ')
    ) p';

EXEC sp_executesql @Query;

DROP TABLE #tbl_price;

SQL Server中的动态透视

1 个答案: