Question

我正在尝试计算MySQL数据库中显示给用户的活动结果数但我只计算行数，但我似乎无法计算有多少活动/非活动/已删除

<?php
  $user_id = $this->session->userdata('user_id');
  $query = $this->custom_query("SELECT post_status FROM listings WHERE user_id=$user_id ");
  if($query->num_rows()>0){
    foreach($query->result() as $row){
      if($row->post_status == 'active'){
        echo $row->num_rows();
      }
    }                   
  }
?>

Answer 1

你可以使用sql count函数，在这里查看有效的函数https://www.w3schools.com/sql/sql_count_avg_sum.asp

回答;

select count(id) as active_count from listings WHERE user_id=$user_id and post_status = 'active'

Answer 2

您可以使用修改后的sql语句尝试此修改后的代码。

一个查询中有多个计数。

 <?php
      $user_id = $this->session->userdata('user_id');

      $query = $this->custom_query("SELECT 
          COUNT(CASE WHEN post_status = 'active' THEN 1 END) as active_total,
          COUNT(CASE WHEN post_status = 'inactive' THEN 1 END) as inactive_total,
          COUNT(CASE WHEN post_status = 'deleted' THEN 1 END) as deleted_total
        FROM listings WHERE user_id = $user_id");

        $row = $query->result();

        echo "Active: ".$row[0]->active_total."<br/>\n";
        echo "Inactive: ".$row[0]->inactive_total."<br/>\n";
        echo "Deleted: ".$row[0]->deleted_total."<br/>\n";
?>

Answer 3

计算检索到的数据库记录的简便方法是在查询中使用num_rows

$user_id = $this->session->userdata('user_id');
return $this->db->get_where('listings', array('user_id'=> $user_id, 'post_status' => 'active'))->num_rows();

在php中计算活动的非活动删除结果

3 个答案: