Question

我正在尝试从webapp获取json数据：

我试过了：

pytz

然后：

from flask import Flask
from flask import request

app = Flask(__name__)

@app.route('/postjson', methods = ['POST'])
def postJsonHandler():
    print (request.is_json)
    content = request.get_json()
    print (content)
    return 'JSON posted'

app.run(port= 8090)

我正在接受：

在服务器端：

import requests

url='http://127.0.0.1:8090/postjson'

hj=requests.post(url,{
 "device":"TemperatureSensor",
 "value":"20",
 "timestamp":"25/01/2017 10:10:05"
})

print(hj.text)

和客户输出：

 * Running on http://127.0.0.1:8090/ (Press CTRL+C to quit)
127.0.0.1 - - [22/Apr/2018 01:45:54] "POST /postjson/ HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:46:01] "GET / HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:46:01] "GET /robots.txt HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:51:46] "GET / HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:51:47] "GET /robots.txt HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:52:26] "GET /postjson' HTTP/1.1" 404 -
127.0.0.1 - - [22/Apr/2018 01:52:48] "GET /postjson/ HTTP/1.1" 404 -

我只想发布json并接收并将其保存到服务器端的变量

Answer 1

发布脚本时只有一个问题。您需要在hj=requests.post(url,json='some json')电话中设置参数，即requests.post
它也可以从def post(url, data=None, json=None, **kwargs):函数定义import requests url='http://127.0.0.1:8090/postjson' hj=requests.post(url,json = { "device":"TemperatureSensor", "value":"20", "timestamp":"25/01/2017 10:10:05" }) print(hj.text)中看出来，所以在你的情况下，你把它作为数据而不是json发送。

textPaint.getTextBounds(text, 0, text.length(), bounds);

怎么解析烧瓶中的json数据？

1 个答案: