Question

该功能应显示与某个值对应的硬币数量;即：56的输入应显示回[25,25,5,1]。

我遇到了麻烦： 1）在阵列中显示2+相同的硬币（我理解下面的数学函数没有正确使用） 2）从数组中删除任何0

感谢您的帮助。

＆＃13;

function getCoins(){
	let coins = [25, 10, 5, 1];
	    amount = prompt ("Enter an amount to convert into coins");
	    coinAmount = "";
					

	for (i = 0; i < coins.length; i++){
		if (amount % coins[i] >= 0){ 
			coinAmount +=  coins[i] * (Math.floor (amount/coins[i])) + ","; 
			amount = amount % coins[i];  	
			console.log (coinAmount)
		} 
	} 
}
		
getCoins()

＆＃13;

Answer 1

一个选项是push数组并使用join来显示它。

您可以使用硬币类型将concat硬币安装到new Array(NumberOfCouns)和fill。

function getCoins() {
  let coins = [25, 10, 5, 1];
  let amount = prompt("Enter an amount to convert into coins");
  let coinAmount = [];


  for (i = 0; i < coins.length; i++) {
    if (Math.floor(amount / coins[i]) > 0) {

      coinAmount = coinAmount.concat(new Array(Math.floor(amount / coins[i])).fill(coins[i]));
      amount = amount - (Math.floor(amount / coins[i]) * coins[i]);
    }
  }

  console.log(coinAmount.join())
}

getCoins();

Answer 2

这个怎么样？

function getCoins(){
    let coins = [25, 10, 5, 1];
        amount = prompt ("Enter an amount to convert into coins");
        coinAmount = "";


    for (i = 0; i < coins.length; i++){
        if (amount >= coins[i]){ 
            var integer = parseInt(amount/coins[i]);
            coinAmount +=  integer + ","; 
            amount -= integer*coins[i];     
            console.log (coinAmount);
        }
        else{
            coinAmount += "0,";
            console.log (coinAmount);
        }
    } 
}

getCoins()

输入30：

1,
1,0,
1,0,1,
1,0,1,0,

因为我们有1个值为25的硬币和1个值为5的硬币

输入25：

1,
1,0,
1,0,0,
1,0,0,0,

如何一次多次向数组添加一个元素

2 个答案: