我是新的承诺。
我正在使用nodejs promisify,所以我将以下声明声明为Redis的承诺
const { promisify } = require('util');
const getAsync = promisify(client.get).bind(client);
const hmsetAsync = promisify(client.hmset).bind(client);
const hsetAsync = promisify(client.hset).bind(client);
const incrAsync = promisify(client.incr).bind(client);
const smembersAsync = promisify(client.smembers).bind(client);
const keysAsync = promisify(client.keys).bind(client);
const sismemberAsync = promisify(client.sismember).bind(client);
我有以下功能,我不知道在哪里放置决心(消息)
function sendMessage(senderId = '', roomId = '', text = '', type='text') {
var message = {}
return new Promise( function (resolve, reject) {
if (senderId == '') {
reject('Invalid Characters in Sender Id or Sender Id is empty.');
}
if (roomId == '') {
reject('Invalid Characters in Room Id or Room Id is empty.');
}
if (text == '') {
console.log('Text:' ,text);
reject('Invalid Characters in Text or Text is empty.');
}
//Check if Room Exist
keysAsync('room-'+roomId).then((value) => {
value == '' && reject('Room '+roomId+ ' does not exist.');
sismemberAsync('roomuser-'+roomId, senderId).then((ismember)=> {
ismember == 0 && reject('User ' + senderId + ' is not a member of room ' + roomId);
const datetime = new Date();
incrAsync('messageId')
.then((id) => {
//Create the message Hash
hmsetAsync('messsage:'+id, 'id', id, 'roomId', roomId, 'senderId', senderId, "created", datetime, "text", text);
//add message to Set
saddAsync('roommessages-'+roomId, id);
message = { id: id, roomId: roomId, senderId: senderId, created: datetime, text: text }
resolve(message) //If i place here i don't get the resolve.
}).catch(err => reject(err))
}).catch(err => reject(err))
}).catch(err => reject(err))
})
}
然后我试着像这样调用这个函数
tools.sendMessage(3, 4, 'Does this work?','text').then((result)=> {
console.log('Send Message Result => ',result);
}).catch(err => {
console.log(err)
});
如果我将解决方案(消息)放在现在的位置,则上述承诺无法解决,并且“发送消息结果”根本不显示。
如果我将它放在链承诺之外,则var消息返回一个空对象{}
我的问题:我需要将解决方案放在需要多次承诺调用的此类函数中,因为我需要等待多次redis检查?
我有许多功能需要在我继续进行下一步操作之前进行所有redis调用。
答案 0 :(得分:1)
我可能会考虑重构您的代码,如下所示。如果您需要在临时.then()
阶段捕获错误,请使用onrejected回调。
function sendMessage(senderId = '', roomId = '', text = '', type='text') {
return keysAsync('room-'+roomId)
.then(value => value === '' ? Promise.reject('Room '+roomId+ ' does not exist.')
: sismemberAsync('roomuser-'+roomId, senderId))
.then(ismember => ismember === 0 ? Promise.reject('User ' + senderId + ' is not a member of room ' + roomId)
: incrAsync('messageId'))
.then(id => { var datetime =new Date();
hmsetAsync('messsage:'+id, 'id', id, 'roomId', roomId, 'senderId', senderId, "created", datetime, "text", text);
saddAsync('roommessages-'+roomId, id);
return { id: id, roomId: roomId, senderId: senderId, created: datetime, text: text };
})
.then(message => doSomethingWith(message))
.catch(errorHandler);
}
在上面的代码中,我将new Date()
移到了实际使用的下方的一个阶段,但如果出于某种原因,您需要在原始datetime
阶段.then()
,如您的问题所示那你也可以这样做;
function sendMessage(senderId = '', roomId = '', text = '', type='text') {
return keysAsync('room-'+roomId)
.then(value => value === '' ? Promise.reject('Room '+roomId+ ' does not exist.')
: sismemberAsync('roomuser-'+roomId, senderId))
.then(ismember => ismember === 0 ? Promise.reject('User ' + senderId + ' is not a member of room ' + roomId)
: Promise.all([incrAsync('messageId'), new Date()]))
.then(([id, datetime]) => { hmsetAsync('messsage:'+id, 'id', id, 'roomId', roomId, 'senderId', senderId, "created", datetime, "text", text);
saddAsync('roommessages-'+roomId, id);
return { id: id, roomId: roomId, senderId: senderId, created: datetime, text: text };
})
.then(message => doSomethingWith(message))
.catch(errorHandler);
}