Android Volley Params

Question

在我的项目中，我从JSONobject请求传递params中的用户的名字。然后它会得到响应并填充文本视图。但是，我无法弄清楚为什么我的代码不起作用。我检查了我的PHP，当我在其中放入一个预定义的名字时它工作正常，所以我排除了一个Web服务问题。它首先获得响应然后通过参数吗？请帮忙

public class ProfileActivity extends AppCompatActivity {

TextView Username, Firstname, Lastname, Birthdate, Barangay;

String firstname;
String json_url = "http://localhost/android/getprofileinfo.php";



@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_profile);

    Username = (TextView)findViewById(R.id.usernameprofile);
    Firstname = (TextView)findViewById(R.id.firstnameprofile);
    Lastname = (TextView)findViewById(R.id.lastnameprofile);
    Birthdate = (TextView)findViewById(R.id.birthdayprofile);
    Barangay = (TextView)findViewById(R.id.barangayprofile);

   final Bundle bundle = getIntent().getExtras();

    firstname = bundle.getString(firstname);





    JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, json_url, (String) null,
            new Response.Listener<JSONObject>() {
                @Override
                public void onResponse(JSONObject response) {
                    try {
                        Username.setText(response.getString("username"));
                        Firstname.setText(response.getString("firstname"));
                        Lastname.setText(response.getString("lastname"));
                        Birthdate.setText(response.getString("birthdate"));
                        Barangay.setText(response.getString("barangay"));
                    }

                    catch(JSONException e){
                            e.printStackTrace();
                    }

                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

            Toast.makeText(ProfileActivity.this, "Something went wrong", Toast.LENGTH_SHORT).show();
            error.printStackTrace();
        } //end of method onErrorResponse

    })
    {
        @Override
        protected Map<String, String> getParams() throws AuthFailureError {
            Map<String, String> params = new HashMap<String, String>();
            params.put("firstname", firstname);
            return params;
        }
    };
    MySingleton.getmInstance(ProfileActivity.this).addTorequestque(jsonObjectRequest);

}

}

这是getpropileinfo.php

<?php

$firstname =$_POST["firstname"];


define('HOST','localhost');
define('USER','root');
define('PASS','');
define('DB','mydb');

$con = mysqli_connect(HOST,USER,PASS,DB) or die('Unable to Connect');

$sql = "SELECT username,firstname,lastname,birthdate,barangay FROM users 
WHERE firstname LIKE '".$firstname."'; ";

$result = mysqli_query($con, $sql);

if(mysqli_num_rows($result) > 0)
{
$row = mysqli_fetch_assoc($result);
echo json_encode(array("username"=>$row['username'], 
"firstname"=>$row['firstname'], 
    "lastname"=>$row['lastname'], "birthdate"=>$row['birthdate'], 
"barangay"=>$row['barangay']));
}
?>

Answer 1

您未正确使用<?php $gl_TBLNAME = ""; $gl_QUERYSTRING = ""; function getCache($useCache, $serverQUERYSTRING, $serverPOST, $serverFILENAME) { $ret = ""; if ($useCache === true) { global $LGCACHEPDO; global $gl_TBLNAME; global $gl_QUERYSTRING; $gl_QUERYSTRING = $serverQUERYSTRING; if ($gl_QUERYSTRING == "") { foreach ($serverPOST as $key => $value) $gl_QUERYSTRING = $gl_QUERYSTRING . $key . "=". urlencode($value) . "&"; $gl_QUERYSTRING = rtrim($gl_QUERYSTRING, "&"); } $gl_TBLNAME = $serverFILENAME; $getcache_PRST = $LGCACHEPDO->prepare("SELECT output FROM " . $gl_TBLNAME . " WHERE querystring = :querystring"); $getcache_PRST->bindValue(":querystring", $gl_QUERYSTRING); $getcache_PRST->execute() or die($LGCACHEPDO->errorInfo()); if ($getcache_PRST->rowCount() == 1) { $getcache_RSLT = $getcache_PRST->fetch(PDO::FETCH_ASSOC, PDO::FETCH_ORI_NEXT); $ret = $getcache_RSLT["output"]; } } return $ret; } // more functions here ?> ，请使用您的通话活动getExtras()提供您传递的密钥名称，例如

在调用活动传递意图中，如

putExtra()

然后在ProfileActivity中，

Intent i = new Intent(FirstActivity.this, ProfileActivity.class);   
String strName = "some_name";
i.putExtra("key_username", strName);
startActivity(i);

转换为final Bundle bundle = getIntent().getExtras(); firstname = bundle.getString("key_username");

JsonArrayRequest

Answer 2

可能是您的本地主机问题，Go through Genymotion正在使用您的PC IP地址。获取您的IP地址：

开始 - ＆gt; cmd - ＆gt; IPCONFIG 然后搜索IPv4，复制IP并将其粘贴到您的URL中。它应如下所示：

String YourURL =“http://192.168.0.106:8888/android/getprofileinfo.php”;

希望这也适合你。

Answer 3

在方法参数中，删除json对象的字符串强制转换。

null代替(String) null。

Answer 4

将您的JSONRequest更改为StringRequest。