Question

我正在做一个小任务。任务是对货币分配器计算器进行编程。基本版本可能会产生以下输出：

Initial amount ($): 348
$100
$100
$100
$20
$20
$5
$2
$1

这是我的尝试：

#Pseudocode:
"""
Ask user for amount
For each demonination in [100, 50, 20, 10, 5, 2, 1]:
    Integer-divide amount by demonination
    Subtract demonination from amount to leave residual
    If residual // demonination > 1, add 1 to the count of this note, and repeat
    Otherwise go to the next denomination
"""


def find_denom(amount):
    number_of_notes = 0
    banknotes = [100, 50, 20, 10, 5, 2]
    for note in banknotes:
        residual = (amount // note)
        if residual // note > 1:
            number_of_notes += 1
    return residual, number_of_notes

amount = int(input("Enter initial amount ($): "))
residual, number_of_notes = find_denom(amount)

如果我输入348作为初始金额，我会得到以下变量值：amount=348，number_of_notes=3，这对于amount中的$ 100条记的数量是正确的，residual=174 1}}。

我只是想让我的find_denom功能先行，但我不确定从哪里开始。

Answer 1

在其他方面，为了实现你想要的，使用可以使用这个功能

def find_denom(amount):
    banknotes = [100, 50, 20, 10, 5, 2, 1]
    for note in banknotes:
        counter = 0 # reassign zero to counter for every loop
        if note <= amount:
            number_of_notes = amount // note  # get the number of each note in amount
            amount = amount % note  # assign the remaining amount to amount
            while counter < number_of_notes: # check it the number of counter has exceeded the number of notes 
                print('$'+str(note)) #convert note to str and concatenate $ with it and display the note
                counter += 1

amount = int(input("Enter initial amount ($): "))
find_denom(amount)

Answer 2

您命名为residual的变量不是残差，而是该笔记的计数。要获得残差，请将笔记乘以计数，然后从金额中减去该数。您也可以使用%模数运算符获得相同的数字。

您应该找到小于金额的第一张钞票，然后执行计算。

def find_denom(amount):
    banknotes = [100, 50, 20, 10, 5, 2]
    for note in banknotes:
        if note <= amount:
            number_of_notes = amount // note
            residual = amount % note
            return residual, number_of_notes
    return amount, 0

使用％和//查找除数

2 个答案: