使用另一个对象作为参数

Question

我想在网站上搜索“搜索”的每个国家/地区的JSON数据属性名称

let array = {
    continents: [
    {
      name: "Europe",
      countries: [
        {
          name: "Austria",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Germany",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    },
    {
      name: "Asia",
      countries: [
        {
          name: "Thailand",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Japan",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    }
  ]
};

预期的行为是当我输入“an”时结果将是一个类似的数组：

let array = {
    continents: [
    {
      name: "Europe",
      countries: [
        {
          name: "Germany",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    },
    {
      name: "Asia",
      countries: [
        {
          name: "Thailand",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Japan",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    }
  ]
};

所以我们将摆脱奥地利

如何实现这一目标？我们应该使用fliter函数（基准测试显示它很慢，基于：https://jsperf.com/function-loops/11）。我们也可以在大陆名称

中搜索

现在我知道如何记录正确的值，但是如何从中组合正确的数组？

let array = {
  continents: [
    {
      name: "Europe",
      countries: [
        {
          name: "Austria",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Germany",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    },
    {
      name: "Asia",
      countries: [
        {
          name: "Thailand",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Japan",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    }
  ]
};

searchValue = "an";

for (let i = 0; i < array.continents.length; i++) {
  for (let j = 0; j < array.continents[i].countries.length; j++) {
    if (
      array.continents[i].countries[j].name
        .toLowerCase()
        .includes(searchValue.toLowerCase())
    ) {
      console.log(array.continents[i].countries[j].name);
    }
  }
}

Answer 1

嗯..创建一个空数组，并在符合搜索条件时推送国家名称：

＆＃13;

＆＃13;

const array = {
  continents: [{
      name: "Europe",
      countries: [{
          name: "Austria",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Germany",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    },
    {
      name: "Asia",
      countries: [{
          name: "Thailand",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        },
        {
          name: "Japan",
          adresses: {
            1: "one",
            2: "two",
            3: "three"
          }
        }
      ]
    }
  ]
}

const searchValue = "an"
let result = []

array.continents.forEach(e =>
  e.countries.forEach(v =>
    v.name.toLowerCase().includes(searchValue) && result.push(v.name))
)

console.log(result)

＆＃13;

＆＃13;

＆＃13;