Question

在Python 3和pandas中我有这个数据帧：

import pandas as pd

ano_2016_exec = pd.read_excel('emendas/emendas_executadas_autores_2016.xls',sheet_name='Sheet1', decimal = ",")

ano_2016_exec.info()
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 10428 entries, 0 to 10427
Data columns (total 9 columns):
Autor               10427 non-null object
Emenda              10427 non-null object
UO_Ajustada         10427 non-null object
Funcional           10427 non-null object
Acao_e_Subtitulo    10427 non-null object
Valor_aprovado      10428 non-null float64
Empenhado           10428 non-null float64
Depesa_Executada    10428 non-null float64
Pago                10428 non-null float64
dtypes: float64(4), object(5)
memory usage: 733.3+ KB

在原始文件中，列＆＃34; Valor_aprovado＆＃34;，＆＃34; Empenhado＆＃34;，＆＃34; Despesa_Executada＆＃34;和＆＃34;帕果＆＃34;是带小数点的数字 - ＆gt; ＆＃34;＆＃34 ;.例如：

3647087716,31449 -> represents in decimal "." 3,647,087,716.31449
498820,7 -> 498,820.7

但是加载的文件将这些列转换为float，并带有符号：

colunas_selecionadas = [＆＃34; Valor_aprovado＆＃34;，＆＃34; Empenhado＆＃34;，＆＃34; Depesa_Executada＆＃34;，＆＃34; Pago＆＃34;] ano_2016_exec [colunas_selecionadas]。头（）

Valor_aprovado  Empenhado   Depesa_Executada    Pago
0   9.100292e+09    7.268573e+09    7.268573e+09    3.647088e+09
1   6.471218e+06    6.471218e+06    6.471218e+06    0.000000e+00
2   1.200000e+06    3.421430e+05    3.421430e+05    1.710710e+05
3   7.471218e+06    6.713361e+06    6.713361e+06    0.000000e+00
4   2.000000e+05    1.000000e+05    1.000000e+05    1.000000e+05

像：

7.268573e+09 
3.647088e+09
6.471218e+06

我希望这些数字出现在我的数据框中，带有两位小数而不是表示法。像这样：

7,268,572,739.83
3,647,087,716.31

拜托，这可能吗？

我应该如何正确加载数据文件＆＃39; emendas_executadas_autores_2016.xls＆＃39;？

Answer 1

Set a locale that interprets numbers in this way. The Spanish locale does so: es_ES.UTF-8

Use this parameter in the same way as listed here - but for the opposite purpose: How do I use Python to convert a string to a number if it has commas in it as thousands separators?

在pandas中如何正确加载带小数的值＆＃34;，＆＃34;？

1 个答案: