Question

新手在这里，通常道歉。所以我非常基础和完全自学（=通过从网站复制代码来学习，主要是在这里）。

==＆GT;背景＆lt; == 最终，我试图创建taskwarrior依赖关系的分层显示。我认为我需要完成的步骤是：

TW导出 - ＆gt; JSON
JSON导入到python
找到关键所在的条目＆＃39;存在（这些是父任务）
提取＆＃39;取决于＆＃39; pair（这些是子任务的UUID）
在导入的JSON中查找这些值（以获取子任务描述）
以漂亮的，可读的顺序显示

我已经陷入了第5步。

==＆GT;问题＆lt; == 我应该如何构建我的查找逻辑呢？

非常感谢提前。

WGII

import json

inputfile=open('data_file.json', encoding='utf-8')
pydata=json.load(inputfile)

for parent in pydata:
    if "depends" in parent:
        print(parent['description'])
        for child in pydata:
            if child['uuid'] = parent[depends]:
                print(child['description'])

---编辑---添加错误信息＆amp;编号为编辑行：

Traceback (most recent call last):
  File "~/json0.py", line 10, in <module>
    if child['uuid'] == parent[depends]:
NameError: name 'depends' is not defined

json：

 [
 {"id":1,"depends":["e6e559c6-742d-4862-9eca-a0f100e1cdb9"],"description":"redacted_1","entry":"20180406T204008Z","modified":"20180406T211650Z","status":"pending","uuid":"842003ce-b52f-4a1c-b6b2-7586c5e5defe","urgency":-4.92877},
 {"id":2,"description":"redacted_2","entry":"20180406T211113Z","modified":"20180406T215713Z","status":"pending","uuid":"e6e559c6-742d-4862-9eca-a0f100e1cdb9","urgency":8.07123},
 {"id":3,"description":"redacted_3","entry":"20180406T211224Z","modified":"20180406T221728Z","status":"pending","uuid":"184c1e8b-acf0-4cf3-b2d5-8130e5cb2cca","urgency":8.07123},
 {"id":4,"description":"redacted_4","due":"20180404T230000Z","entry":"20180406T215603Z","modified":"20180406T222147Z","priority":"H","start":"20180406T222147Z","status":"pending","uuid":"770aa058-ba48-453c-8070-6bb32279e7c8","urgency":22.0712},
 {"id":5,"description":"redacted_5","entry":"20180406T223551Z","modified":"20180406T223951Z","start":"20180404T230000Z","status":"pending","uuid":"69e44b6e-0a55-48d7-b659-352753ae19ae","annotations":[{"entry":"20180406T223716Z","description":"now"}],"urgency":4.87123},
 {"id":6,"description":"redacted_6","entry":"20180420T123738Z","modified":"20180420T123738Z","status":"pending","uuid":"0c470063-92ae-4893-b7de-bd9b9f94fb04","urgency":0}
 ]

一些系统信息： xubuntu 16.04 thonny 2.1.16 python 3.6.4

-----编辑2 ---------------遵循Prateek的帮助-------------

好的，我越来越近了：

import json

inputfile=open('data_file.json', encoding='utf-8')
pydata=json.load(inputfile)

ID_descr = {}
for z in pydata:
    ID_descr[z['uuid']]= [z['description']]

for parent in pydata:
    if "depends" in parent:   
        print(parent['description'])
        childNo=(parent['depends'])
        print(childNo)
        print(ID_descr[(childNo)])

输出+错误消息：

redacted_1
['e6e559c6-742d-4862-9eca-a0f100e1cdb9']
Traceback (most recent call last):
  File "~/json0.py", line 17, in <module>
    print(ID_descr[(childNo)])
TypeError: unhashable type: 'list'

尝试了最后一行的几种变体，但无法弄清楚如何使用ID_descr dict查找来处理变量＆＃39;。

例如。带/不带括号＆amp;有/无＆＃34; ＆＃34;或者＆＃39; ＆＃39; - 没有帮助

例如。我试图将字符串化childNo=str(parent['depends'])

但这只是给我一个差异错误：KeyError: "['e6e559c6-742d-4862-9eca-a0f100e1cdb9']"

Answer 1

json在pydata转换为字典要获取内部值，您需要根据需要解析字典。

首先将所有子ID保存在列表或词典中
打印这些儿童ID的说明。

代码

child_task_dic = dict()
# Get all child ids from JSON
for parent in pydata:
        # print('id ' + str(parent['id']) + ':' + parent['description'])
        if 'depends' in parent:
            child_task_dic[parent['id']]= parent['depends']

for k,v in child_task_dic.items():
    print('Parent task id : ' + str(k))
    for y in pydata:
        if y['uuid'] in v:
            print('\t' + 'Child task id ' + y['uuid'])
            print('\tStatus : ' + y['description'])

输出

{1: ['e6e559c6-742d-4862-9eca-a0f100e1cdb9']}
Parent task id : 1
    Child task id e6e559c6-742d-4862-9eca-a0f100e1cdb9
    Status : redacted

python json使用来自另一个搜索的值进行查找

1 个答案:

代码

输出