OpenMPI生成，分散和收集

Question

我使用编程语言c在openMPI中新增了，我使用函数MPI_SPAWN()来生成从主服务器到工作服务器的其他进程，我也使用了函数{{1 }＆amp; MPI_Gather()分割数组并将其发送给工人并从中收集结果。

结果似乎是：

MPI_Scatter()

这是我的代码：

主人：

the rank : 2 

the rank : 3 

0 0 0 0

the rank : 0 

0 1073741824 0 1073741824

0 -1879048192 0 -1879048192 

the rank : 1 

0 -1073741824 0 -1073741824 

工人：

int main(int argc, char *argv[]) {

    int rank,n_spawns = 4;
    int *msg = malloc(sizeof(int)* n_spawns*4);
    int *msg1 = malloc(sizeof(int)* n_spawns*4);
    int *recvbuf = malloc(sizeof(int) * n_spawns);


    srand(0);
    for(int i=0;i<4*n_spawns;i++) {
        msg[i] = rand() % 20;
        printf("%d ", msg[i]);
    }


    MPI_Init(&argc, &argv);
    MPI_Comm intercomm;
    MPI_Comm_rank(MPI_COMM_WORLD, &rank);
    MPI_Comm_spawn("/Users/a/Desktop/Study/AAPCours/FirstOMPI/worker", 
    MPI_ARGV_NULL, n_spawns, MPI_INFO_NULL, 0, MPI_COMM_SELF, 
    &intercomm,MPI_ERRCODES_IGNORE);

    MPI_Scatter(msg, n_spawns, MPI_INT, &recvbuf, n_spawns, MPI_INT, 
    MPI_ROOT, intercomm);
    MPI_Gather(&recvbuf, n_spawns, MPI_INT, msg, n_spawns, MPI_INT, 0, 
    intercomm);
    for (int i = 0; i<4*n_spawns; i++) {
         printf("%d ", msg[i]);
    }

    MPI_Finalize();
    return 0;
 }

是的，有人能帮帮我吗？