Question

如果我进行单元测试，

  test('it saves included instances', async() => {
    /* Get "water" composition */
    const compositions = await _compositions.findAll(
        {include: [{model: _elements, where: {name: 'water'}}, _atoms]});

    /**
     * compositions[0] -> Hydrogren
     * compositions[1] -> Oxygen
     */
    let hydrogen = compositions[0].get('atom');
    /* rename "Hydrogen" to "My super Hydrogen" */
    hydrogen.name = 'My super Hydrogen';

    /* save the composition */
    compositions[0].save();

    /* Get a fresh Hydrogen Instance from the database */
    hydrogen = await _atoms.find({where: {symbol: 'H'}});
    expect(hydrogen.name)
        .to.equal('My super Hydrogen', 'wrong, the value is still Hydrogen');
  });

我希望该值等于先前从相关对象保存的值。

atom的属性composition是外键：

compositionModel.belongsTo(await getAtomModel(), {foreignKey: 'atom_id'});

Answer 1

在Sequelize中更新对象时，应该在实例本身上调用.update

test('it saves included instances', async() => {
  const compositions = await _compositions.findAll(
      {include: [{model: _elements, where: {name: 'water'}}, _atoms]});
  let hydrogen = compositions[0].get('atom');

  let newName = 'My super Hydrogen';
  compositions[0].update({
      name: newName
  });

  /* Get a fresh Hydrogen Instance from the database */
  hydrogen = await _atoms.find({where: {symbol: 'H'}});
  expect(hydrogen.name)
      .to.equal(newName);
});

Sequelize不会保存包含的对象

1 个答案: