Question

function Resource(name = "undefined", count= 0) {
  this.name = name;
  this.count= count;
}

function Building(name = "undefined", count= 0, cost= 0) {
  this.name = name;
  this.count= count;
  this.cost= cost;
}

function NewBuilding(name) {
  Building[Buildz] = new Building(name);
  createBuildingBtn(name);
  Buildz++;
}

function NewResource(name) {
  Res[Resz] = new Resource(name);
  createResourceDiv(name);
  Resz++;
}

我有这个代码，＆＃34; Building＆＃34;与资源几乎完全相同。资源工作，但建立dosnt。我希望你能帮助我。

Answer 1

您在同一范围内有一个名为Building的函数和一个名为Building的数组。将您的阵列名称更改为其他名称，它可以正常工作Resource有效，因为您为其附带的数组（Res）使用了不同的名称。

Builds = [];
Res = []
Buildz = 0;
Resz = 0;

function Resource(name = "undefined", count= 0) {
  this.name = name;
  this.count= count;
}

function Building(name = "undefined", count= 0, cost= 0) {
  this.name = name;
  this.count= count;
  this.cost= cost;
}

function NewBuilding(name) {
  Builds[Buildz] = new Building(name);
  Buildz++;
}

function NewResource(name) {
  Res[Resz] = new Resource(name);
  Resz++;
}

NewBuilding("Test");
NewResource("Test2");

console.log(Builds);

为什么＆＃34;建设＆＃34;不是建构者，而是＆＃34;资源＆＃34;是什么？

1 个答案: