Question

我有下表：

oDateTime              Value
----------------------------------------------
2017-01-01 00:00:00    10
2017-01-01 00:00:01    20
2017-01-01 00:00:02    10
2017-01-01 00:00:03    10
ff.

每行日期的行数据为每秒。我希望得到以下结果：

oDateTime              Value
----------------------------------------------
2017-01-01 01:00:00    10

所以它是每个日期的小时平均值知道怎么做吗？

谢谢。

Answer 1

DATEADD(HOUR, DATEDIFF(HOUR, 0, oDateTime), 0)会将任何DATETIME值舍入到小时。这使您可以将DateHour值保持为单个列。

SELECT
  DATEADD(HOUR, DATEDIFF(HOUR, 0, oDateTime), 0),
  SUM(value) / 60.0,
  AVG(value)
FROM
  yourTable
GROUP BY
  DATEADD(HOUR, DATEDIFF(HOUR, 0, oDateTime), 0)

编辑：减少重复次数，但稍长一点......

SELECT
  rounded.DateHour,
  SUM(value) / 60.0,
  AVG(value)
FROM
  yourTable
CROSS APPLY
  (VALUES(DATEADD(HOUR, DATEDIFF(HOUR, 0, oDateTime), 0))) AS rounded(dateHour)
GROUP BY
  rounded.DateHour

Answer 2

尝试按日期和小时进行汇总：

SELECT
    CONVERT(varchar, oDateTime, 112) AS date,
    DATEPART(hour, oDateTime) AS hour,
    AVG(Value) AS Value
FROM yourTable
GROUP BY
    CONVERT(varchar, oDateTime, 112),
    DATEPART(hour, oDateTime);

日期平均值每秒时间SQL

2 个答案: