如何定义异步装置并在异步测试中使用它们?
以下代码全部在同一个文件中,失败了。是否由测试运行员明确地调用夹具而不是等待?
@pytest.fixture
async def create_x(api_client):
x_id = await add_x(api_client)
return api_client, x_id
async def test_app(create_x, auth):
api_client, x_id = create_x
resp = await api_client.get(f'my_res/{x_id}', headers=auth)
assert resp.status == web.HTTPOk.status_code
制造
==================================== ERRORS ====================================
_____________ ERROR at setup of test_app[pyloop] ______________
api_client = <aiohttp.test_utils.TestClient object at 0x7f27ec954f60>
@pytest.fixture
async def create_x(api_client):
> x_id = await add_x(api_client)
...
... cannot show the full trace and pathnames sorry
...
in __await__
ret = yield from self._coro /home/mbb/.pyenv/versions/3.6.3/envs/mr/lib/python3.6/site-packages/aiohttp/test_utils.py:245: in request
method, self.make_url(path), *args, **kwargs /home/mbb/.pyenv/versions/mr/lib/python3.6/site-packages/aiohttp/helpers.py:104: in __iter__
ret = yield from self._coro /home/mbb/.pyenv/versions/mr/lib/python3.6/site-packages/aiohttp/client.py:221: in _request
with timer:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
self = <aiohttp.helpers.TimerContext object at 0x7f27ec9875c0>
def __enter__(self):
task = current_task(loop=self._loop)
if task is None:
> raise RuntimeError('Timeout context manager should be used '
'inside a task') E RuntimeError: Timeout context manager should be used inside a task
/home/mbb/.pyenv/versions/mr/lib/python3.6/site-packages/aiohttp/helpers.py:717: RuntimeError
=========================== 1 error in 1.74 seconds ============================ Process finished with exit code 0
我知道我可以做到
@pytest.fixture
def create_x(loop, api_client):
x_id = loop.run_until_complete(add_x(api_client))
return api_client, x_id
但我想知道是否存在更简单/最优雅的方式。我无法在pytest,pytest-asyncio,pytest-aiohttp的项目页面中找到一个清晰简单的示例/解释。
我使用Python 3.6.3,pytest 3.4.2,pytest-asyncio 0.8.0和pytest-aiohttp 0.3.0
非常感谢您的帮助
答案 0 :(得分:12)
您只需将测试标记为异步
@pytest.mark.asyncio
async def test_app(create_x, auth):
api_client, x_id = create_x
resp = await api_client.get(f'my_res/{x_id}', headers=auth)
assert resp.status == web.HTTPOk.status_code
这告诉pytest在事件循环中运行测试而不是直接调用它。
灯具可以标记为正常
@pytest.fixture
async def create_x(api_client):
x_id = await add_x(api_client)
return api_client, x_id
答案 1 :(得分:2)
协程函数本身不受PyTest的支持,因此您需要为其安装其他框架
如果使用pytest-aiohttp,您的问题将以这种方式解决
import asyncio
import pytest
from app import db
url = 'postgresql://postgres:postgres@localhost:5432'
@pytest.fixture(scope='session')
def loop():
return asyncio.get_event_loop()
@pytest.fixture(scope='session', autouse=True)
async def prepare_db(loop):
async with db.with_bind(f'{url}/postgres') as engine:
await engine.status(db.text('CREATE DATABASE test_db'))
await db.set_bind(f'{url}/test_db')
await db.gino.create_all()
yield
await db.bind.close()
async with db.with_bind(f'{url}/postgres') as engine:
await engine.status(db.text('DROP DATABASE test_db'))
主要思想是使用同步loop-fixture
,它将由异步设备使用