Question

我在mysql中构建了以下查询。并尝试了很多转换为laravel但没有成功。

SELECT u.id, u.purchase_item_name,u.sales_item_name, us.type,
GROUP_CONCAT(p.itemcode) AS purchase_items,
GROUP_CONCAT(s.itemcode) as sales_items 
FROM composite_inventories as u 
LEFT JOIN composite_has_inventories as us ON u.id = us.composite_inventory_id 
LEFT JOIN inventories as s ON US.inventory_id = s.id AND us.type='sale'
LEFT JOIN inventories as p ON US.inventory_id = p.id AND us.type='purchase'
GROUP BY u.id

我正在尝试上面查询laravel datatabel查询，但它给出了如下错误。

SQLSTATE [42000]：语法错误或访问冲突：1055＆＃39; saas.composite_inventories.purchase_item_name＆＃39;不在GROUP BY中（SQL：选择GROUP_CONCAT（p.itemcode）作为purchase_items，GROUP_CONCAT（s.itemcode）作为sales_items，composite_inventories。id，composite_inventories。{{ 1}}，purchase_item_name。composite_inventories，sales_item_name。us来自type，加入composite_inventories作为composite_has_inventories us } {。{1}} = composite_inventories。id在[{1}} us上composite_inventory_id左inventories加入s。US = {{1} {。inventory_id和s。id =＆＃39;在us上type inventories左右加入p。{{ 1}} = US。inventory_id和p。id =＆＃39;按us购买＆＃39;分组type）

我在laravel查询下尝试过。

composite_inventories

我刚试过下面的查询

id

以上查询在显示数据表时有效。但是当我尝试搜索过滤器时，它会给出以下错误，因为purchase_items和sales_items字段在数据库中不存在但只是别名。错误是

异常消息：↵↵SQLSTATE[42000]：语法错误或访问冲突：1583对本机函数的调用中的参数不正确＆＃39; LOWER＆＃39; （SQL：选择计数为聚合来自（选择$result = Compositeinventory::select([ DB::raw('GROUP_CONCAT(p.itemcode) as purchase_items'), DB::raw('GROUP_CONCAT(s.itemcode) as sales_items'), 'composite_inventories.id', 'composite_inventories.purchase_item_name', 'composite_inventories.sales_item_name', 'us.type' ])->leftJoin('composite_has_inventories as us', 'composite_inventories.id', '=', 'us.composite_inventory_id') ->leftJoin('inventories as s', function($join) { $join->on('US.inventory_id', '=', 's.id'); $join->on('us.type','=',DB::raw("'sale'")); }) ->leftJoin('inventories as p', function($join) { $join->on('US.inventory_id', '=', 'p.id'); $join->on('us.type','=',DB::raw("'purchase'")); }) ->groupBy('composite_inventories.id')->get();。$row = DB::table('composite_inventories as u')->select([ 'u.id', 'u.purchase_item_name', 'u.sales_item_name', DB::raw('GROUP_CONCAT(p.itemcode) as purchase_items'), DB::raw('GROUP_CONCAT(s.itemcode) as sales_items') ])->leftJoin('composite_has_inventories as us', 'u.id', '=', 'us.composite_inventory_id') ->leftJoin('inventories as s', function($join) { $join->on('US.inventory_id', '=', 's.id'); $join->on('us.type','=',DB::raw("'sale'")); }) ->leftJoin('inventories as p', function($join) { $join->on('US.inventory_id', '=', 'p.id'); $join->on('us.type','=',DB::raw("'purchase'")); }) ->groupBy('u.id', 'u.purchase_item_name','u.sales_item_name');，u。id，u。purchase_item_name，GROUP_CONCAT（p。 itemcode）作为purchase_items，GROUP_CONCAT（s.itemcode）作为u的sales_items，sales_item_name将composite_inventories作为u composite_has_inventories us u id。 = us。composite_inventory_id在[{1}} inventories = s。US上inventory_id左加入s id。us =＆＃39;促销＆＃39;在[{1}} type上inventories p。US = {{1} }。inventory_id和p。id =＆＃39;购买＆＃39;其中（LOWER（us为type）LIKE％a％或LOWER （composite_inventories为u.purchase_item_name）LIKE％a％或LOWER（composite_inventories为u.purchase_items）LIKE％a％或LOWER（composite_inventories为u.sales_item_name ）composite_inventories u.sales_items，u，id，u。purchase_item_name）count_row_table）

Answer 1

这不是laravel的问题，您的查询无效，因为它包含一些未聚合且未在group子句中提及的列。要更正此问题，您需要将group by子句更新为

group by u.id, u.purchase_item_name,u.sales_item_name, us.type

在查询构建器

中

->groupBy('composite_inventories.id', 'composite_inventories.purchase_item_name','composite_inventories.sales_item_name', 'composite_has_inventories.type')

如果每个composite_inventories有多个type（s），那么我猜你也需要GROUP_CONCAT，并从group by子句中删除这个列。

更新语法错误，您没有正确使用lower函数只需将要转换为值的列名称传递给小写，如

WHERE (
      LOWER(u.purchase_item_name) LIKE '% a %'
      OR LOWER(u.purchase_items) LIKE '% a %'
      OR LOWER(u.sales_item_name`) LIKE '% a %' 
      OR LOWER(u.sales_items) LIKE '% a %'
)

如果您的数据库排序规则未设置为区分大小写，则无需使用lower()功能获取更多信息，请查看B.5.4.1 Case Sensitivity in String Searches

此外，如果您在查询中使用mysql fucntions，则可能需要使用laravel的查询构建器的raw()方法

将mysql查询转换为雄辩的查询问题

1 个答案: