列中的5个或更多

Question

不使用HAVING，如果总计为5或更多，我怎样才能让SQL结果在COUNT列中显示总和？
  

SELECT DISTINCT
[ID],
COUNT(CASE WHEN [ICN] >=5 THEN 1 END) AS 'COUNT'

FROM DBO.[OFD]
WHERE [YEAR] = 2018
AND [LOCATION-ID] = '0021'

GROUP BY [ID],
[ICN]

当我输入以下代码时，我得到的结果与下面的例子类似......

SELECT DISTINCT
[ID],
[ICN]

FROM DBO.[OFD]
WHERE [YEAR] = 2018
AND [LOCATION-ID] = '0021'


GROUP BY [STUDENT-ID],
[INCIDENT-NO]

Example of Results I get Example of Results I want

Answer 1

请尝试此查询。希望这可能会有所帮助

;WITH cte_data (id,NumberOfrows)
AS
(
SELECT ID, COUNT(*)NumberOfrows
FROM DBO.[OFD] t 
WHERE [YEAR] = 2018
AND [LOCATIONID] = '0021'
AND INNO>=5
GROUP BY ID
)
SELECT DISTINCT t.id, isnull(NumberOfrows ,0) NumberOfrows
FROM DBO.[OFD] t
LEFT JOIN cte_data t1 on t1.id = t.id
WHERE t.[YEAR] = 2018
AND t.[LOCATIONID] = '0021'

Answer 2

您需要检查＆lt; 5并使用sum而不是count

SELECT DISTINCT
  [ID],
  SUM(CASE WHEN [INNO] >=5 THEN 1 ELSE 0 END) AS 'COUNT'
FROM DBO.[OFD]
WHERE [YEAR] = 2018
  AND [LOCATION-ID] = '0021'
GROUP BY [ID],[INNO]

更改为

SELECT DISTINCT
  SUM(CASE WHEN [INNO] >=5 THEN 1 ELSE 0 END) AS 'COUNT'
FROM DBO.[OFD]
WHERE [YEAR] = 2018
  AND [LOCATION-ID] = '0021'