Question

我试图用数组从每个数组中删除第3个元素。

我有什么：

data =
[["51.9435","-4.26697","450","125"],
["51.9437","-4.26717","450","125"],
["51.9438","-4.26733","450","125"],
["51.944","-4.26748","450","125"]]

我需要什么：

data =
[["51.9435","-4.26697","125"],
["51.9437","-4.26717","125"],
["51.9438","-4.26733","125"],
["51.944","-4.26748","125"]]

我假设使用拼接，但我想不出如何将它用于2d数组。

Answer 1

在每个子阵列上使用splice。

const data = [["51.9435","-4.26697","450","125"],
              ["51.9437","-4.26717","450","125"],
              ["51.9438","-4.26733","450","125"],
              ["51.944","-4.26748","450","125"]]

for( const array of data )
   array.splice(2, 1)
   
console.log(data)

编辑：为了保持原始数据的完整性，您需要在拼接之前复制数组。

const data = [["51.9435","-4.26697","450","125"],
              ["51.9437","-4.26717","450","125"],
              ["51.9438","-4.26733","450","125"],
              ["51.944","-4.26748","450","125"]]

const converted = data.map(function(array){
   const copy = array.slice()
   copy.splice(2, 1)
   return copy
})

console.log(data)
console.log(converted)

Answer 2

您可以使用以下代码段

＆＃13;

data =[["51.9435","-4.26697","450","125"],
       ["51.9437","-4.26717","450","125"],
       ["51.9438","-4.26733","450","125"],
       ["51.944","-4.26748","450","125"]];
data.map( (arr) => {arr.splice(2,1);});
console.log(data);

＆＃13;

Answer 3

您可以将<html> <body> <div id="move"></div> </body> </html>与.map()一起使用。

.splice()创建一个新数组，其值从回调函数返回。
.map()从数组中删除一个或多个元素。

<强>演示：

.splice()

<强>文档：

Answer 4

如果您只想删除一个元素，则可以使用mObsInt.set(mObsInt.get()+1);提供您要删除的索引的索引splice和2。

从2D数组中的每个数组中删除特定元素

4 个答案: