主程序应该要求密码为8个字符,1个上限,1个下限和1个字符。 1位数。一旦通过要求,它应该要求用户重新输入密码并检查两个密码是否匹配。我需要帮助将该部分添加到我的代码中。目前,代码编译没有问题。
import java.util.Scanner;
public class PassChecker2 {
public static void main (String [] args) {
Scanner input = new Scanner(System.in);
String inputPassword;
System.out.println(" Please enter your Password:");
inputPassword = input.next();
System.out.println(checkerPass(inputPassword));
System.out.println("");
//main(args);
}
public static boolean lenthgCk (String password) {
if (password.length() > 7) {
if(checkerPass(password)) {
return true;
}
}
else {
System.out.println("Password must be at least 8 characters long.");
return false;
}
return true;
}
public static boolean checkerPass (String password) {
boolean hasUpperCase = false;
boolean hasLowerCase = false;
boolean hasDigit = false;
char c;
for (int i = 0; i < password.length(); i++) {
c = password.charAt(i);
if(Character.isUpperCase(c)) {
hasUpperCase = true;
}
else if(Character.isLowerCase(c)) {
hasLowerCase = true;
}
else if(Character.isDigit(c)) {
hasDigit = true;
}
if(hasUpperCase && hasLowerCase && hasDigit) {
return true;
}
else {
System.out.println("Password is invalid must meet all requirements.");
return false;
}
}
return true;
}
}
答案 0 :(得分:1)
只需输入另一个字符串,就像输入原始密码一样,并检查它们是否相同:
System.out.println(" Please confirm your Password:");
Stirng confirmPassword = input.next();
if (!confirmPassword.equals(inputPassword)) {
System.out.println("Passwords do not match");
// And possibly exit the program here?
}