Question

每当我在PHP页面中输入任何数据时，它会不断添加0作为数据库。 it says 0 in the mysql table 我是一名新生，我真的不明白错误在哪里。

这是我的PHP和表单编码。

<form name="Submit" method="post" action="signupconn.php">
<p>
  <input type="text" name="textfield" id="teachersname">
</p>
<p>
  <input type="text" name="textfield2" id="teachersphone">
</p>
<p>
  <textarea name="textarea" id="teachersadd"></textarea>
</p>
<p>
  <input type="text" name="textfield3" id="teachersic">
</p>
<p>
  <input type="text" name="textfield6" id="teachersqualify">
</p>
<p><input type="text" name="textfield7" id="classassigned"></p>
<p>
  <input type="text" name="textfield4" id="teachersusername">
</p>
<p>
  <input type="text" name="textfield5" id="teacherspassword">
</p>
<p>&nbsp;</p>
<p><input type="reset" value="Reset">
<input type="submit" value="Sign Up"></p>
</form>
<?php
$server="localhost"; //host Name
$username="root"; //Mysql username
$password=""; //Mysql password
 $dbname="taska_ceria_"; //Database name

 //Creating connection to mysqli.
 $conn=new mysqli($server,$username,$password,$dbname);

  //checking connection

  if($conn->connect_error){
  die("Connection failed" . $conn->connect_error);
  }

  if(isset($_POST['submit'])){
  $teachersname = 
  mysqli_real_escape_string($conn,$_POST['teachersname']);
  $teachersphone = 
  mysqli_real_escape_string($conn,$_POST['teachersphone']);$teachersadd 
  = mysqli_real_escape_string($conn,$_POST['teachersadd']);
  $teachersic = mysqli_real_escape_string($conn,$_POST['teachersic']);
  $teachersqualify = 
  mysqli_real_escape_string($conn,$_POST['teachersqualify']);
  $classassigned = 
  mysqli_real_escape_string($conn,$_POST['classassigned']);
  $teachersusername = 
  mysqli_real_escape_string($conn,$_POST['teachersusername']);
  $teacherspassword = 
  mysqli_real_escape_string($conn,$_POST['teacherspassword']);

   }

 $sql= "INSERT INTO 
 teachersinfo(teachersname,teachersic,teachersphone,teachersadd,
 teachersqualify,classassigned,teachersusername,teacherspassword)  VALUE 
 ('$teachersname','$teachersphone','$teachersadd','$teachersic',
 '$teachersqualify','$classassigned','$teachersusername',
 '$teacherspassword')";

  if($conn->query($sql) === TRUE){
   echo "Record Added Succesfully";
   header("location:body.php");
    }
   else
    {
  echo "Error" . $sql . "<br/>" . $conn->error;
   }
   $conn->close();
   ?>

当我输入数据时，表示数据已成功输入，但在mysql表中，每个属性的数据内容都为0。

3.请别人帮助我。

Answer 1

您已将id用作输入帖子，

<input type="text" name="textfield" id="teachersname">

在名称字段上使用teachersname。

<input type="text" name="teachersname" id="teachersname">

然后它可以正常工作

无法将正确的数据输入MySQLi，它会一直显示0作为数据

1 个答案: