Question

尝试运行此代码时，出现

的关键错误

KeyError: <tkinter.Button object .!button4>

所有按钮1-5的按钮编号不同。

我不明白它是什么意思，因为我以为我指的是正确的按钮。请帮忙！这是我的代码：

import tkinter as tk

def button_click(event = None):
    which_button = event.widget
    var = f[which_button]

    if var in f:
        var.set(f[var])
    else:
        for i, j in enumerate(v):
            if j == v[i]:
                var.set(k[i])

window = tk.Tk()
window.title("Flashcards")
k=[]
v=[]

f={"Bonjour": "Hello",
   "Lundi": "Monday",
   "Parler": "To Talk",
   "Manger": "To Eat",
   "Dormir": "To Sleep"}

for key,val in f.items():
    k.append(key)
    v.append(val)

for i in range(5):
    s = tk.StringVar()
    s.set(k[i])

    b = tk.Button(window, textvariable = s, width = 10)
    b.bind("<Button-1>", button_click)
    b.grid(row = 0, column = i)

window.mainloop()

Answer 1

迟到的回答，但是：为什么在Button有回调函数时使用bind？使用partial()，您可以为每个按钮指定一个特定的回调。

import tkinter as tk
from functools import partial

def button_click(event=None, key=None):
    print(key, '-', f[key])

window = tk.Tk()
window.title("Flashcards")

f={"Bonjour":"Hello","Lundi":"Monday","Parler":"To Talk",
   "Manger":"To Eat","Dormir":"To Sleep"}
for i,key in enumerate(f.keys()):
    b = tk.Button(window, text=key, width = 10)
    b.bind("<Button-1>", partial(button_click, key=key))
    b.grid(row = 0, column = i)

window.mainloop()

如果您不熟悉partial，则它与lambda:类似，但语法不同。

KeyError：<tkinter.button object =“”。！button =“”>

1 个答案: