在int main(int argc, char *argv[])
{
int a = 100000, b = 90000;
printf("%ld\n%ld\n", product_wrong(a, b), product_right(a, b));
return 0;
}
long product_wrong(int a, int b)
{
return (long) (a * b);
}
long product_right(int a, int b)
{
return (long) a * b;
}
中,我有一个包含3个对象的数组,其值为:1000,2000,3000。我想创建一个函数,当用户输入1和1之间的数字时。 1000你得到了对象
state.1.extras.mileage
当输入介于1000和1000之间时2000你将得到第二个对象, 当你输入2000和3000之间时,你会得到第三个对象。
这是我目前的职能:
{
name: '1.000 mileage',
mileage: '1.000',
description: 'mileage-description',
},
答案 0 :(得分:1)
你有一个包含三个对象的数组,每个对象都有一个里程值。使用javascript find
函数,您将获得满足您所声明条件的第一个值。
你的职能:
getObject(speed) {
const mileage= [
{
name: '1000 mileage',
mileage: '1000',
description: 'mileage-description',
},
{
name: '2000 mileage',
mileage: '2000',
description: 'mileage-description 2',
},
{
name: '3000 mileage',
mileage: '3000',
description: 'mileage-description 3',
}
];
return mileage.find(obj => parseInt(obj.mileage, 10) >= speed);
}
以下代码段:
var speed = [800, 1000, 1001, 995, 2000, 2958, 3000];
console.log(speed);
var getMileage = (speed) => {
const mileage= [
{
name: '1000 mileage',
mileage: '1000',
description: 'mileage-description',
},
{
name: '2000 mileage',
mileage: '2000',
description: 'mileage-description 2',
},
{
name: '3000 mileage',
mileage: '3000',
description: 'mileage-description 3',
}
];
return mileage.find(obj => parseInt(obj.mileage, 10) >= speed);
};
console.log(speed.forEach(s => console.log(s, 'object: ', getMileage(s))));