Question

有一些网址类型：

https://mysite.com/page-title
https://mysite.com/category/page-title
https://mysite.com/category/123-page-title(123-它的页面ID）

我需要检查URL，是否以数字开头（类型3）。 I.e url =是类型3，然后返回TRUE。

这需要什么样的正则表达式？

Answer 1

据我所知，ID可以在域名地址之后的任何地方，因此：

false https: //mysite.com/123-page-title
false https: //mysite.com/page-title
false https: //mysite.com/category/page-title
true  https: //mysite.com/category/123-page-title
false  https: //mysite.com/1-page-title

因此，您需要的正则表达式为：'/mysite\.com.*/category/\d+?.*/'

mysite\.com.*/\d+?.*
   mysite matches the characters mysite literally (case sensitive)
   \. matches the character . literally (case sensitive)
   com matches the characters com literally (case sensitive)
 .* matches any character (except for line terminators)
    * Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)
    /category/ matches the characters /category/ literally (case sensitive)
    \d+? matches a digit (equal to [0-9])
      +? Quantifier — Matches between one and unlimited times, as few times as possible, expanding as needed (lazy)
 .* matches any character (except for line terminators)
   * Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)

在此处查看：https://regex101.com/r/qv8tim/2

Answer 2

我对正则表达式满足此要求的建议如下：

.*?category\/[0-9]+.*

这将匹配短语category/之前的任何内容，然后要求至少跟随一个数字，然后匹配该行的其余部分。

Answer 3

每个人都喜欢正则表达式： - ）

不使用regex的解决方案：

function is_valid($url)
{
    $pieces = explode('/', parse_url($url, PHP_URL_PATH));
    return isset($pieces[2]) && (int)$pieces[2];
}

查看实际操作：https://3v4l.org/BqcTs

正则表达式。如果/ category /以数字开头的部分URL返回true。怎么样？

3 个答案: