Question

在我的代码中，医生显示在谷歌地图上，每位医生都有一些属性用户按任何属性或属性进行搜索，如果用户输入地址＆＃34; USA＆＃34;专业化是＆＃34; Heart＆＃34;然后只会显示那些医生，其地址和专业化如下：

因此用户可以输入许多组合和我无法理解如何实现这些过滤器，

我的代码是

  private void showdoctorresult() {
    final String selectedspec = dr_spec_spiner.getSelectedItem().toString();
    final String selecedgender = gender_spiner.getSelectedItem().toString();
    final String enteredaddress = mapsearchaddress.getText().toString();
    final String enteredfee = mapsearchfee.getText().toString();
    final String enteredtime = mapsearchtime.getText().toString();

    DatabaseReference doctordRef = FirebaseDatabase.getInstance().getReference().child("Users").child("Doctor");
    mMap.clear();
    doctordRef.addListenerForSingleValueEvent(new ValueEventListener() {
        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {


            for (DataSnapshot child : dataSnapshot.getChildren()) {
                // SaveDonorData doctordata = dataSnapshot.getValue(SaveDonorData.class);
                String latitude = child.child("latitude").getValue().toString();
                String longitude = child.child("longitude").getValue().toString();
                String donarname = child.child("user_name").getValue().toString();
                String drspec = child.child("specialization").getValue().toString();
                String draddress = child.child("user_address").getValue().toString();
                String dr_time = child.child("time").getValue().toString();
                String dr_fee = child.child("fee").getValue().toString();
                String dr_gender = child.child("gender").getValue().toString();
                spec.add(drspec);
                double loclatitude = Double.parseDouble(latitude);
                double loclongitude = Double.parseDouble(longitude);
                LatLng cod = new LatLng(loclatitude, loclongitude);

                if(!selectedspec.matches("") || !selecedgender.matches("") || !enteredaddress.matches("") || !enteredfee.matches("")|| !enteredtime.matches("")){
                    if(selectedspec.toLowerCase().contains(drspec.toLowerCase()) && enteredaddress.toLowerCase().contains(draddress.toLowerCase()) && selecedgender.matches(dr_gender) && enteredfee.matches(dr_fee) && enteredtime.matches(dr_time)){
                        mMap.addMarker(new MarkerOptions().position(cod).title(donarname));
                        mMap.moveCamera(CameraUpdateFactory.newLatLngZoom(cod,15));
                    }
                } else
                if(!selectedspec.matches("") || !selecedgender.matches("") || !enteredaddress.matches("") || !enteredfee.matches("") ){
                    if(selectedspec.toLowerCase().contains(drspec.toLowerCase())&& enteredaddress.toLowerCase().contains(draddress.toLowerCase())  && selecedgender.matches(dr_gender) && enteredfee.matches(dr_fee)  ){
                        mMap.addMarker(new MarkerOptions().position(cod).title(donarname));
                        mMap.moveCamera(CameraUpdateFactory.newLatLngZoom(cod,15));
                    }
                }else
                if(!selectedspec.matches("") || !selecedgender.matches("") || !enteredaddress.matches("") ){
                    if(selectedspec.toLowerCase().contains(drspec.toLowerCase()) && selecedgender.matches(dr_gender)&& enteredaddress.toLowerCase().contains(draddress.toLowerCase())     ){
                        mMap.addMarker(new MarkerOptions().position(cod).title(donarname));
                        mMap.moveCamera(CameraUpdateFactory.newLatLngZoom(cod,15));
                    }
                }else
                if(!selectedspec.matches("") || !selecedgender.matches("") ){
                    if(selectedspec.toLowerCase().contains(drspec.toLowerCase()) && selecedgender.matches(dr_gender)   ){
                        mMap.addMarker(new MarkerOptions().position(cod).title(donarname));
                        mMap.moveCamera(CameraUpdateFactory.newLatLngZoom(cod,15));
                    }
                }else
                if(!selectedspec.matches("")  ){
                    if(selectedspec.toLowerCase().contains(drspec.toLowerCase())   ){
                        mMap.addMarker(new MarkerOptions().position(cod).title(donarname));
                        mMap.moveCamera(CameraUpdateFactory.newLatLngZoom(cod,15));
                    }
                }
            }
        }

        @Override
        public void onCancelled(DatabaseError databaseError) {

        }


    });
}

我如何制作逻辑来搜索医生，用户可以输入任何字段并获得结果请回答我在此先感谢

Answer 1

进行sql查询并触发firebase存储，如下面的代码，你可以改变。

private void sqlQuery(){
    DatabaseReference reference = FirebaseDatabase.getInstance().getReference();

    Query query = reference.child("usersDb").child("UserTable").orderByChild("email").equalTo("vikas@gmail.com");
    query.addListenerForSingleValueEvent(new ValueEventListener() {
        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {
            if (dataSnapshot.exists()) {

                for (DataSnapshot issue : dataSnapshot.getChildren()) {
                    Log.d("Value::",issue.getValue(User.class).email);
                }
            }
        }

        @Override
        public void onCancelled(DatabaseError databaseError) {

        }
    });
}

Answer 2

所以回答的第一个问题（我认为你有）将是＆＃34;是用户查询＆＃39; AND＆＃39;或者＆＃39;或者＆＃39;＆＃34; - 就像我在寻找所有女性，心脏病专家一样，＆＃39; 或者我正在寻找所有的女医生或心脏病专家＃39;

所以假设它是一个AND，每条记录的逻辑如下：

  onDataChange

     // set flags for each filter based on if any selection made
     set 'specialtySet' to true if selectedSpec not empty string.
     set 'genderSet' to true if selectedGender not empty string.
     // repeat for each filter...

     set lastMarkerLoc = null

     for each child loop

        set 'addMarker' to false

        if 'specialtySet'
           if specialty matches
              set 'addMarker' to true
           else
              // This is the 'AND' all specified filters must pass test.
              // If instead you wanted 'OR' then eliminate the 'continue'
              continue // loop
           endif
        endif

        if 'genderSet'
           if gender matches
              set 'addMarker' to true
           else
              continue // loop
           endif
        endif

        //... repeat similar logic for each filter

        if 'addMarker' is true
           addMarker()
           // no need to move camera for every result
           set 'lastMarkerLoc' to this location

        endif
     endloop

     // zoom camera
     if 'lastMarkerLoc' != null 
        zoom camera to 'lastMarkerLoc'
     endif


  end onDataChange

PS - 修复＆＃39; SEARCH＆＃39;按钮。

在Google地图上过滤Android中某些属性的位置

2 个答案: